Answer: The actual free-energy change for the reaction -8.64 kJ/mol.
Explanation:
The given reaction is as follows.
Fructose 1,6-bisphosphate 
Glyceraldehyde 3-phosphate + DHAP
For the given reaction, 
is 23.8 kJ/mol.
As we know that,
Here, R = 8.314 J/mol K, T = 
= (37 + 273) K
= 310.15 K
Fructose 1,6-bisphosphate = 
M
Glyceraldehyde 3-phosphate = 
M
DHAP = 
M
Expression for reaction quotient of this reaction is as follows.
Reaction quotient = ![\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BDHAP%5D%5B%5Ctext%7Bglyceraldehyde%203-phosphate%7D%5D%7D%7B%5B%2Ftext%7BFructose%201%2C6-bisphosphate%7D%5D%7D)
Q = 
= 
Now, we will calculate the value of 
as follows.
= 
= -8647.73 J/mol
= -8.64 kJ/mol
Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.
Delta H is negated. Multiply by -1
<span>respiratory and circulatory </span>
From the balanced chemical reaction, we can see that for
every 4 moles of Fe (iron) formed, the heat released or heat of reaction is
1.65 x 10^3 kJ.
So calculate the moles of iron first:
moles iron = 250 g / (55.85 g/mol) = 4.48 mol
So the heat of reaction is:
δhrxn = (-1.65 x 10^3 kJ / 4 mol) * (4.48 mol) = -1.85 kJ
Answer:
La réponse ce trouve en bas
Explanation:
13 a) Oui, ce possible parce la solubilité du sel dans l'eau a 60° est majeur que 50g du sel en 150 ml d'eau (333.3 g/L). Dans la graphique la solubilité est de 370 g/L.
b) Jusqu'au 30°C, (30°, 360g(L), ce trouvent ces points dans la ligne rouge.
