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shtirl [24]
3 years ago
10

Giovanni created this chart to study for an exam.

Chemistry
2 answers:
Olegator [25]3 years ago
7 0
Calcium carbonate is indeed used as an antacid (among Mg(OH)2, Al2(OH)3 and NaHCO3).

Ferrous oxide or Iron (II) oxide is a dark substance, and I would certainly think twice before using a dark tooth paste (Yew! ) It might even rust if left in the mouth for some time!

max2010maxim [7]3 years ago
7 0
<h3><u>Answer;</u></h3>

B) Swap the uses for iron oxide and calcium carbonate.

<h3><u>Explanation;</u></h3>
  • Calcium carbonate is a compound that is naturally found in marble, chalk and limestone. It is used in pharmaceutical applications as a cost <u>effective dietary calcium supplement, and also used in antacids.</u>
  • Calcium carbonate is also found in <u>products such as baking powder, tooth paste, and wine among others.</u>
  • Iron oxides are compounds of iron that are<u> used as coloring agents in some cosmetics.</u> The forms of iron oxides used in cosmetics are normally synthetic.
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HURRY! 10 POINTS!!
frosja888 [35]

Answer:

Weak bonds require less energy to form than strong bonds

Explanation:

According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.

As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.

Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.

6 0
3 years ago
A pure copper penny contains approximately 2.9×1022 copper atoms. Use the following definitions to determine how many ______ of
hammer [34]

Complete question is;

A pure copper penny contains approximately 2.9 × 10^(22) copper atoms.

1 doz = 12

1 gross = 144

1 ream = 500

1 mol = 6.022 × 10^(23)

Use these definitions to determine the following:

A) How many dozens of copper atoms are in a penny.

B) How many gross of copper atoms are in a penny

C) How many reams of copper atoms are in a penny.

D) how many moles of copper atoms are in a penny?

All answers can be rounded to two significant figures

Answer:

A) 2.4 × 10^(21) dozens

B) 2.01 × 10^(20) gross

C) 5.8 × 10^(19) reams

D) 0.048 mol

Explanation:

A) A dozen contains 12.

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/12 dozens = 2.42 × 10^(21).

In 2 significant figures, we have;

2.4 × 10^(21) dozens

B) 1 gross = 144

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/144 gross ≈ 2.01 × 10^(20) gross

C) 1 ream = 500

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/500 reams = 5.8 × 10^(19) reams

D) 1 mol = 6.022 × 10^(23)

Therefore, 2.9 × 10^(22) copper atoms will contain;

(2.9 × 10^(22))/(6.022 × 10^(23)) = 0.048 mol

6 0
3 years ago
A relationship in which one variable increases as the other variable decreases is an inverse relationship.
Brut [27]

Answer:

TRUE

Explanation:

HOPE IT WILL HELP YOU

8 0
3 years ago
Calculate the mass of khc8h4o4 that reacts with 15 ml of the naoh solution
dlinn [17]
The balanced chemical reaction would be:

 KHC8H4O4<span> (aq) + </span>NaOH<span> (aq) → NaKC8H4O4 (aq) + H2O.

The concentration of the NaOH is equal 0.1 M. We use this and the volume given above to determine the mass of KH</span>C8H4O4. We do as follows:

0.1 mol / L NaOH (.015 L) ( 1 mol KHC8H4O4 / 1 mol NaOH) (204 g / 1 mol) = 0.306 g KHC8H4O4


6 0
3 years ago
6. Determine the wavelength for a photon of light
MAVERICK [17]

Answer:

6) λ  =  0.84 × 10⁻⁸ m

7) λ  =  0.84 × 10⁻⁶ m

Explanation:

6) Given data:

Wavelength of photon = ?

Frequency of photon = 3.56 × 10¹⁶ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  = 3.56 × 10¹⁶ Hz ×  λ

λ  =  3×10⁸ m/s   / 3.56 × 10¹⁶ s⁻¹

λ  =  0.84 × 10⁻⁸ m

7) Given data:

Wavelength of photon = ?

Frequency of photon = 6.15 × 10¹⁴ Hz

Solution:

Formula:

Speed of radiation = frequency × wavelength

c = speed of wave = 3×10⁸ m/s

by putting values,

3×10⁸ m/s  =  6.15 × 10¹⁴ Hz ×  λ

λ  =  3×10⁸ m/s   /  6.15 × 10¹⁴ Hz s⁻¹

λ  =  0.84 × 10⁻⁶ m

6 0
3 years ago
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