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2 years ago

4. A balloon is filled with 3.0 L of helium at 310 K. The balloon is placed in an oven where the

Chemistry

1 answer:

77julia77 [94]2 years ago

4 0

Answer:

3,29L

Explanation:

3.29L = V2

Formula: V1/T1 = V2/T2

--------------------

Given:

V1 = 3.0 L V2 = ?

T1 = 310 K T2 = 340 K

--------------------

Plugin:

(X stands in place of V2 just to make it easier to look at)

[3.0L / 310K = X / 340K]

(3.0L / 310K = 0.01L/K)

0.01L/K = X / 340K

(multiply 340K on both sides, it cancels out on the right)

0.01L/K * 340K = X

(0.01L/K * 340K = 3.29L)

**3.29L = X**

[or]

**3.29L = V2**

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Digestion starts in the mouth. What two digestive processes occur there?

FinnZ [79.3K]

Answer: Mechanical digestion from chewing, chemical digestion from saliva

Explanation:

7 0

2 years ago

Read 2 more answers

If 24.1 g of sodium hydroxide react with 22.0 g of hydrochloric acid to form 35.3g

disa [49]

Answer:

10.85 g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaOH + HCl —> NaCl + H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation.

These can be obtained as illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH from the balanced equation = 1 × 40 = 40 g

Molar mass of H2O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Summary:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Finally, we shall determine the mass of water, H2O produced from the reaction as follow:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Therefore, 24.1 g of NaOH will react to produce = (24.1 × 18)/40 = 10.85 g of H2O.

Therefore, 10.85 g of H2O were produced from the reaction.

4 0

3 years ago

How many grams of calcium are required to free 8 grams of hydrogen gas from hydrochloride acid, HCl?

Gala2k [10]

Answer:

The answer to your question is 160 g of Calcium

Explanation:

Data

mass of Calcium = ?

mass of Hydrogen = 8 g

reactant = HCl

Process

1.- Write the balanced chemical reaction

Ca + 2HCl ⇒ CaCl₂ + H₂

2.- Look for the atomic number of Calcium and hydrogen

Calcium = 40 g

Hydrogen = 1 x 2 = 2 g

3.- Use proportions to calculate the mass of calcium needed.

40 g of Calcium ---------------- 2 g of hydrogen

x ----------------- 8 g of hydrogen

x = (8 x 40) / 2

x = 320/2

x = 160 g of Calcium

4 0

3 years ago

How much heat to change 1 mole of ice at -25 °C to steam at +125 °C? • heat to warm ice - heat to melt ice (no temperature chang

Ahat [919]

Answer : The amount of heat changes is, 56.463 KJ

Solution :

The conversions involved in this process are :

$(1):H_2O(s)(-25^oC)\rightarrow H_2O(s)(0^oC)\\\\(2):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)\\\\(4):H_2O(l)(100^oC)\rightarrow H_2O(g)(100^oC)\\\\(5):H_2O(g)(100^oC)\rightarrow H_2O(g)(125^oC)$

Now we have to calculate the enthalpy change.

$\Delta H=[m\times c_{p,s}\times (T_{final}-T_{initial})]+n\times \Delta H_{fusion}+[m\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{vap}+[m\times c_{p,g}\times (T_{final}-T_{initial})]$

where,

$\Delta H$ = enthalpy change or heat changes = ?

n = number of moles of water = 1 mole

$c_{p,s}$ = specific heat of solid water = $2.09J/g^oC$

$c_{p,l}$ = specific heat of liquid water = $4.18J/g^oC$

$c_{p,g}$ = specific heat of liquid water = $1.84J/g^oC$

m = mass of water

$\text{Mass of water}=\text{Moles of water}\times \text{Molar mass of water}=1mole\times 18g/mole=18g$

$\Delta H_{fusion}$ = enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

$\Delta H_{vap}$ = enthalpy change for vaporization = 40.67 KJ/mole = 40670 J/mole

Now put all the given values in the above expression, we get

$\Delta H=[18g\times 4.18J/gK\times (0-(-25))^oC]+1mole\times 6010J/mole+[18g\times 2.09J/gK\times (100-0)^oC]+1mole\times 40670J/mole+[18g\times 1.84J/gK\times (125-100)^oC]$

$\Delta H=56463J=56.463KJ$ (1 KJ = 1000 J)

Therefore, the amount of heat changes is, 56.463 KJ

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2 years ago

How many moles of C6H12O6 are consumed if 6 moles of O2 are consumed?

Orlov [11]

This reaction is known as respiration and in order to understand the stoichometry better, we first write the reaction equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

From the equation, we can see that the molar ratio between glucose and oxygen is 1 : 6. Therefore, we can see that if 6 moles of oxygen are consumed, one mole of glucose will be consumed.

4 0

3 years ago