Well, we can be sure that whatever the width is, we can call it ' W '. Then, from information in the question, the length of the garden is ' 3W '.
Now, the perimeter of a rectangle is (length + width + length + width). Using the fancy algebra labels I just gave them, that's (3W + W + 3W + W). And now I can go through that, add up all the Ws, and get a total of 8W for the perimeter.
But he question tells us that the perimeter is 24 yards, so 8W = 24 yds.
Divide each side of that equation by 8, and we discover that W = 3 yds. And if THAT's true, then 3W = 9 yds. Bada bing ! We have the dimensions of the garden.
It's 3 yards wide and 9 yards long.
Answer:
3/4x4/9 least
then 7/7x4/9
then 1 2/3x4/9
Greatest is 2x4/9
Step-by-step explanation:
Abs and piper have a great time at the house
MO = 12 and PR = 3
Solution:
Given
.
Perimeter of ΔMNO = 48
Perimeter of ΔPQR = 12
MO = 12x and PR = x + 2
<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>


Do cross multiplication.


Subtract 48x from both sides.


Divide by 96 on both sides, we get
⇒ 1 = x
⇒ x = 1
Substitute x = 1 in MO an PR.
MO = 12(1) = 12
PR = 1 + 2 = 3
Therefore MO = 12 and PR = 3.
Answer:
Let level of significance is
=0.05
Since p-value is greater than alpha so students' mean score does not significantly differ from the national average.
Correct option is:
His students' mean score does not significantly differ from the national average, because his p-value is greater than alpha.
Let level of significance is
=0.10
Since p-value is less than alpha so students' mean score does significantly differ from the national average.
Correct option is:
His students' mean score does significantly differ from the national average, because his p-value is less than alpha.