The branched structure isomer will require less energy to melt than the straight chain isomer
explanation
Branched structure isomer has weak intermolecular forces of attraction as compared to straight chain isomers. In addition the branched isomer has a low boiling point as compared to straight chain isomers. Since boiling require the of the intermolecular forces tend to have lower boiling point than straight chain
Can you give more information?
CH and O is the reactants while CO and H2O is the products
The solids are characterized as amorphous and crystalline solids based on the arrangement of atoms. The solids that are amorphous are rubber, plastic, candle wax, and glass.
<h3>What are amorphous solids?</h3>
The solids have the arrangement of atoms in the lattice. The solids with an appropriate arrangement of atoms are crystalline solids. For example, sugar, graphite.
The solids with irregular arrangements of atoms in the lattice are amorphous solids. For example, glass, rubber.
Thus, the solids that are amorphous in nature are rubber, plastic, candle wax, and glass.
Learn more about amorphous solids, here:
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Answer:
ΔHr = -103,4 kcal/mol
Explanation:
<u>Using:</u>
<u>AH° (kcal/mol)
</u>
<u>Metano (CH)
</u>
<u>-17,9
</u>
<u>Cloro (CI)
</u>
<u>tetraclorometano (CCI)
</u>
<u>- 33,3
</u>
<u>Acido cloridrico (HCI)
</u>
<u>-22</u>
It is possible to obtain the ΔH of a reaction from ΔH's of formation for each compound, thus:
ΔHr = (ΔH products - ΔH reactants)
For the reaction:
CH₄(g) + Cl₂(g) → CCl₄(g) + HCl(g)
The balanced reaction is:
CH₄(g) + 4Cl₂(g) → CCl₄(g) + 4HCl(g)
The ΔH's of formation for these compounds are:
ΔH CH₄(g): -17,9 kcal/mol
ΔH Cl₂(g): 0 kcal/mol
ΔH CCl₄(g): -33,3 kcal/mol
ΔH HCl(g): -22 kcal/mol
The ΔHr is:
-33,3 kcal/mol × 1 mol + -22 kcal/mol× 4 mol - (-17,9 kcal/mol × 1 mol + 0kcal/mol × 4mol)
<em>ΔHr = -103,4 kcal/mol</em>
<em></em>
I hope it helps!
