The silicon wafer contains 20.96 g of silicon.
The mole of a substance is related to its mass and molar mass by the following equation:
<h3>Mole = mass / molar mass ....... (1)</h3>
Making mass the subject of the above equation, we have
<h3>Mass = mole × molar mass ..... (2)</h3>
With the above formula (i.e equation 2), we can obtain the mass of silicon in the wafer as follow:
Mole silicon = 0.746 mole
Molar mass of silicon = 28.09 g/mol
<h3>Mass of silicon =? </h3>
Mass = mole × molar mass
Mass = 0.746 × 28.09
<h3>Mass of silicon = 20.96 g</h3>
Therefore, the mass of silicon in the wafer is 20.96 g
Learn more: brainly.com/question/24639749
Answer:
is there like a passage to answer this question?
Explanation:
Answer:
A - Increase (R), Decrease (P), Decrease(q), Triple both (Q) and (R)
B - Increase(P), Increase(q), Decrease (R)
C - Triple (P) and reduce (q) to one third
Explanation:
<em>According to Le Chatelier principle, when a system is in equilibrium and one of the constraints that affect the rate of reaction is applied, the equilibrium will shift so as to annul the effects of the constraint.</em>
P and Q are reactants, an increase in either or both without an equally measurable increase in R (a product) will shift the equilibrium to the right. Also, any decrease in R without a corresponding decrease in either or both of P and Q will shift the equilibrium to the right. Hence, Increase(P), Increase(q), and Decrease (R) will shift the equilibrium to the right.
In the same vein, any increase in R without a corresponding increase in P and Q will shift the equilibrium to the left. The same goes for any decrease in either or both of P and Q without a counter-decrease in R will shift the equilibrium to the left. Hence, Increase (R), Decrease (P), Decrease(q), and Triple both (Q) and (R) will shift the equilibrium to the left.
Any increase or decrease in P with a commensurable decrease or increase in Q (or vice versa) with R remaining constant will create no shift in the equilibrium. Hence, Triple (P) and reduce (q) to one third will create no shift in the equilibrium.
Answer:
0.5 mole
Explanation:
C=12u
O=16u
1 mole carbon dioxide=44 grams
so 22grams = 0.5 mole