Answer:
y=3x+3.
Step-by-step explanation:
the given graph intersect the X-axis in (-1;0), the Y-axis in (0;3). Then the slope of the required line is (3-0)/(0+1)=3 and the interception is 3 (point (0;3)).
Finally, the required equation in slope-interception form is y=3x+3.
PERFECT application of the general equation of things
that are moving up and down in gravity:
H(t) = H₀ + v₀t + 1/2 g t²
t = time after the toss
H(t) = height at any time after the toss
H₀ = height from which it's tossed
v₀ = initial speed
g = acceleration of gravity
I'm going to call 'UP' = the positive direction .
So ...
H₀ = +40 ft
v₀ = +54 ft/sec
g = -32 ft/sec²
When the object hits the ground, H(t) = 0 .
So you have ...
0 = 40 + 54 t - 16 t²
Let me re-write that for you, to make it a
little easier and more familiar:
- 16 t² + 54 t + 40 = 0
Divide each side by -2 : 8 t² - 27 t - 20 = 0
Now go to your toolbox, pull out your quadratic formula,
solve that quadratic equation, and you'll get the usual two
solutions.
The positive one is the one you want.
The negative one refers to time before the toss, and may be discarded.
Answer:
x1= 1/2
x2=0,6
Step-by-step explanation:
4x➕6(503-x)=2296
Distribute the 6 into the parentheses
Let x represent the students
503-x will represent the non-students
4x➕3018➖6x=2296
Then combine like terms
-2x➕3018=2296
Now since you move your constant your sign has to change as well,
-2x=2296➖3018
Then subtract
-2x=-722
Then divide both sides by -2
You are left with x=361
This represents the students
503➖361= 142 which equal the non-students
Therefore your answer is:
361=students
142=non-students
Hope this helps! :3
Answer:
-16,-14,-12,-10
Step-by-step explanation:
Let the integers be x, x+2,x+4,x+6
ATQ,
x+x+2+x+4+x+6=-52
4x+12=-52
4x=-52-12
x=-64/4
x=-16
