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2 years ago

PLEASE I WILL MARK BRAINLIEST JUST TELL ME HOW TO SLOVE IT

Mathematics

2 answers:

Bumek [7]2 years ago

7 0

Answer:

x=5

Step-by-step explanation:

So first we want to find x by itself, so we can subtract 4 from both sides:

x=5

That is your simple answer!

Dovator [93]2 years ago

5 0

Step-by-step explanation:

$\huge{ \sf{x + 4 = 9}}$

~ Move 4 to right hand side and change it's sign :

⟼ $\huge{ \sf{x = 9 - 4}}$

~ Subtract 4 from 9

⟼ $\huge{ \sf{x = 5}}$

$\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \bold{ \text{5}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ツ

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Solve the equation. -4n-6=12

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Answer:

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Step-by-step explanation:

-4n=12+6

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n=-18/4

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2 years ago

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When graphed, which function has a horizontal asymptote at 4?

galben [10]

Answer:

Correct answer: C. f(x) = 2(3)x + 4

(please note we changed the expression of the function to exponential form which we believe is the correct form of the question)

Step-by-step explanation:

Horizontal Asymptote

The graph of a function is said to have a horizontal asymptote at y=a if one or both the following limits exist

$\lim\limits_{x \rightarrow \infty}f(x)=a$

$\lim\limits_{x \rightarrow -\infty}f(x)=a$

The horizontal asymptotes are horizontal lines to which the function tends when x increases or decreases without limits.

Let's analyze each one of the options provided:

A. f(x) = 2x -4

$\lim\limits_{x \rightarrow \infty}(2x-4)=+\infty$

$\lim\limits_{x \rightarrow -\infty}(2x-4)=-\infty$

No horizontal asymptote

B. f(x) = -3x + 4

$\lim\limits_{x \rightarrow \infty}(-3x+4)=-\infty$

$\lim\limits_{x \rightarrow -\infty}(-3x+4)=\infty$

No horizontal asymptote

C. f(x) = 2\cdot 3^x + 4

$\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^\infty + 4=\infty$

$\lim\limits_{x \rightarrow \infty}(2\cdot 3^x + 4)=2\cdot 3^{-\infty} + 4=0+4=4$

This function has a horizontal asymptote at y=4

D. 3\cdot 2^x -4

$\lim\limits_{x \rightarrow \infty}(3\cdot 2^x - 4)=3\cdot 2^\infty - 4=\infty$

$\lim\limits_{x \rightarrow \infty}(3\cdot 2^x- 4)=3\cdot 2^{-\infty} - 4=0-4=-4$

This function has a horizontal asymptote at y=-4

Correct answer: C.

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