Ask question

Ask question

All categories

2 years ago

9

A sample of gas occupies 1.2 L at 12.0oC. Assuming pressure remains the same, what would be the volume (in L) of this gas at 67o

C?
A.
1.4

B.
1.0

C.
0.2

D.
5.0

E.
6.7

1 answer:

Levart [38]2 years ago

4 0

Answer:

e.

6.7

hope it help

.

.

.

.

.

.

You might be interested in

Present in a state where it molecules are far apart during a change of state it's molecules slow down which change of state has

blagie [28]

Answer:

The change of state that has occurred is from a gas to a liquid

<em>Note: The question is incomplete. The complete question is given blow.</em>

<em>H₂O is initially present in a state where its molecules are far apart. During a change of state, its molecules slow down. Which change of state has most likely taken place? </em>

<em>from a gas to a liquid </em>

<em>from a liquid to a gas </em>

<em>from a solid to a liquid </em>

<em>from a gas to a plasma</em>

Explanation:

Water can exists in three states: as gaseous water vapor, as liquid water, and as solid ice. Each of these states of water can be interconverted from one to another by the addition or removal of heat in a process known as change of state.

Liquid water can be converted to solid ice by the removal of heat, while solid ice ice can be converted to liquid water by the addition of heat. Also, liquid water can be converted to water vapor by the addition of heat, while water vapor can be converted to liquid water by the removal of heat.

Of the three states of water, the one in which the molecules are farthest apart is in the gaseous state. The molecules have high kinetic energy and move randomly while colliding with one another. When a heat is removed from these highly energetic molecules, the molecules slow down and lose some of their kinetic energy and a change of occurs from gaseous to liquid state.

Therefore, the change of state that occurred as described, is from gas to liquid.

5 0

3 years ago

What is the expected outcome of adding a catalyst to a chemical reaction?

nikitadnepr [17]

The expected outcome would be A. The reaction will speed up after adding a catalyst to a chemical reaction.

4 0

3 years ago

Read 2 more answers

What volume of a 2.10 M NaCl solution is

cluponka [151]

Answer:

146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl

1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x

x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L

It gives the answer and all the working.

To put it another way:

Dividing the amount required by the molar mass

we quickly see that 2.5 moles are required.

One litre of 1.5 molar solution gives 1.5 moles

we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.

3 0

2 years ago

Standard reduction potentials are based on which element?

KonstantinChe [14]

They're based on hydrogen.

6 0

2 years ago

Read 2 more answers

Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic

Kisachek [45]

Answer:

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C) It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9$

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = $164.5\times 10^{-9} g$

$1 ng=10^{-9} g$

Volume of the sample = V = $15.3 cm^3$

Density of the lake water sample ,d= $1.00 g/cm^3$

Mass of sample = M = $d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g$

$ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75$

10.75 is the concentration of arsenic in the sample in parts per billion.

B)

Mass of arsenic in $1 cm^3$ of lake water = $\frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g$

Mass of arsenic in $0.710 km^3$ lake water be m.

$1 km^3=10^{15} cm^3$

Mass of arsenic in $0.710\times 10^{15} cm^3$ lake water :

$m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g$

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

$\frac{2.74}{41.90} days$

Then days required to remove 7,633.66 kg of arsenic from the lake water :

$=7,633.66\times \frac{2.74}{41.90} days=499.19 days$

1 year = 365 days

499.19 days = $\frac{499.19}{365} years = 1.367 years\approx 1.37 years$

It will take 1.37 years to remove all of the arsenic from the lake.

3 0

3 years ago