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3 years ago

Mind helping in these too?

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

On number 9 i’m pretty sure a has a greater surface area because it is 432 and B is 270

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Solve for x. A) -7 C) 6 B) 9 D) 10

Mekhanik [1.2K]

Answer:

Step-by-step explanation:

The segment BC joining the midpoints of 2 sides of the triangle is

Half the length of the third side, that is

x + 31 = 2(x + 19)

x + 31 = 2x + 38 ( subtract x from both sides )

31 = x + 38 ( subtract 38 from both sides )

- 7 = x → A

5 0

3 years ago

Read 2 more answers

margarite owns a boutique. she sells her jewelry at a 30% markup. if she buys a bracelet for $22, what would she sell it for aft

skad [1K]

She would sell it for $26.60 after the markup.

7 0

3 years ago

When completing the square on the equation c2 + 110 = 12, the resulting solution is: It

Delvig [45]

Answer:

$c=1$ and $c=-12$

Step-by-step explanation:

The correct equation is:

$c^2+11c=12$

To solve by completing the square method.

Solution:

We have:

$c^2+11c=12$

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

$c^2+2.\frac{11}{2}c=12$

$c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2=12$ [As $c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2$ ]

Adding both sides by $(\frac{11}{2})^2$

$(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2$

$(c+\frac{11}{2})^2=12+\frac{121}{4}$

Taking LCD to add fraction.

$(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}$

$(c+\frac{11}{2})^2=\frac{169}{4}$

Taking square root both sides.

$\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}$

$c+\frac{11}{2}=\pm\frac{13}{2}$

Subtracting both sides by $\frac{11}{2}$ :

$c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}$

$c=\pm\frac{13}{2}-\frac{11}{2}$

So, we have:

$c=\frac{13}{2}-\frac{11}{2}$ and $c=-\frac{13}{2}-\frac{11}{2}$

$c=\frac{2}{2}$ and $c=\frac{-24}{2}$

$c=1$ and $c=-12$ (Answer)

6 0

4 years ago

Choose Yes or No to tell if the fraction 3 5 will make each equation true. 7 20 + □ = 19 20 Choose... □ + 3 10 = 3 15 Choose...

OleMash [197]

Answer:

True ; false ; False ; true

Step-by-step explanation:

Equation 1:

7 20 + □ = 19 20

19 / 20 - 7/20

(19 - 7) / 20

12/ 20 = 3/5

Equation 2:

□ + 3 10 = 3 15

3/5 + 3/10

(6 + 3) / 10 = 9/10

Equation 3:

1 2 + 2 3 = □

1/ 2 + 2/3

(3 + 4) / 6

7 / 6

Equation 4:

1 10 + 1 2 = □

1/10 + 1/2

(1 + 5) / 10

6 / 10 = 3/5

4 0

3 years ago

Use the law of cosines to find the length of a

borishaifa [10]

Answer:

Step-by-step explanation:

You don't need the Law of Cosines, the Law of sines if what you need. You can't use the Law of Cosines because in order to find side a, you would need the length of side c and you don't have it. Using the Law of Sines is appropriate, knowing that angle B = 55:

$\frac{sin55}{175}=\frac{sin42}{a}$ and solving for a:

$a=\frac{175sin42}{sin55}$ so

a = 143.0

4 0

3 years ago