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sergey [27]
1 year ago
14

2 upper N upper O subscript 2 (g) right arrow 2 upper N upper o (g) plus upper O subscript 2 (g). Second: 2 upper N upper O (g)

right arrow upper N subscript 2 (g) plus upper O subscript 2 (g). Third: upper N subscript 2 (g) plus 2 upper O subscript 2 (g) right arrow upper N subscript 2 upper O subscript 4 (g). What is the equation for the overall reaction obtained by adding these equations?
Chemistry
1 answer:
Ipatiy [6.2K]1 year ago
5 0

The equation for the overall reaction obtained by adding these equations is;  2NO₂(g) ⇒ N₂O₄(g)

<h3>How to simplify chemical equations?</h3>

We are given equations;

2NO₂(g) ----> 2NO(g) + O₂(g)   ---(1)

2NO(g) -----> N₂(g) + O₂(g)   -----(2)

N₂(g) + 2O₂(g) ----> N₂O₄(g)   -----(3)

Add eq 1 and eq 2 to get;

2NO₂(g) + 2NO(g) ⇒ 2NO(g) + O₂(g) + N₂(g) + O₂(g)

2NO will cancel out to get;

2NO₂(g) ⇒ N₂(g) + 2O₂(g)   -----(4)

Add eq 3 to eq 4 to get;

N₂(g) + 2O₂(g) + 2NO₂(g) ⇒ N₂O₄(g) + N₂(g) + 2O₂(g)

This will reduce to;

2NO₂(g) ⇒ N₂O₄(g)

The correct question is;

Consider the chemical equations shown here.

2NO₂(g) ----> 2NO(g) + O₂(g)

2NO(g) -----> N₂(g) + O₂(g)

N₂(g) + 2O(g) ----> N₂O₄(g)

What is the equation for the overall reaction obtained by adding these equations?

Read more about chemical equations at; brainly.com/question/19837884

#SPJ1

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Molar Mass H2O: 18 g/mol 
<span>Molar Mass of Eugenol: 164 g/mol </span>
<span>Boiling point of H2O: 100 degrees C </span>
<span>Boiling point of Eugenol: 254 degrees C </span>
<span>Density of water: 1.0 g/mL </span>
<span>Density of Eugenol: 1.05 g/mL </span>

<span>Using formula:
V= [mole fraction x molar mass] / density </span>

<span>mH20: 0.9947 * 18
          = 17.9046 / 1 g/mL
          = 17.9046 </span>
<span>morg: 0.0053 * 164  
        = 0.8692/ 1.05 g/mL
        = 0.8278 </span>

<span>V% = Vorg/(Vorg + VH2O) * 100 </span>
<span>(0.8278/18.7324) * 100 = 4.419% </span>

Yotal volume = 30 mL; therefore, 
<span>0.0442 = (volume eugenol/30) </span>

<span>(m eug/mH2O) = (peug*164/pH2O*18) </span>
<span>(m eug/30) = (4*164/760*18) </span>
<span>m eug = about 1.44g and </span>
<span>
volume = mass/density
            = 1.44/1.05
            = about 1.37 mL </span>
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2 years ago
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