Answer:
The number of active sites enzyme have is 1.
Explanation:
Mass of penicillinase = 4.10 μg =
1 g = 1000000 μg
The turnover number of the enzyme at 28 °C =
Moles of penicillinase =
Mass of antiboitic-amoxicillin =2.83 mg =
Moles of amoxicillin =
Moles of reactant which are converted into product per second:
=
Moles of product converted in 29.6 seconds:
Number of sites:
<span> Positive Ion - Occurs when an atom loses an electron (negative charge) it has more </span>protons<span> than electrons.</span>
Answer:
0.625 moles of CO₂ can be produced by this reaction.
27.5 g of CO₂
Explanation:
A reaction where CO₂ can be produced is combustion.
The reactants are methane (in this case) and oxygen, while the products will be CO₂ and H₂O.
The balanced reaction is: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)
We assume the oxygen is in excess, so the methane gas, is the limiting reagent.
We convert the mass to moles (mass / molar mass) → 10 g / 16 g/mol = 0.625 moles
According to stoichiometry, 1 mol of methane can produce 1 mol of CO₂. Therefore If we have 0.625 moles of CH₄ we produce 0.625 moles of CO₂. Ratio is 1:1.
Let's convert the moles to mass → (mol . molar mass) =
0.625 mol . 44 g/mol = 27.5 g
Answer: Non-polar covalent bond
Explanation: If two atoms have no difference between their electronegativity charges, they will form nonpolar covalent bonds. This means that the electrons will be shared with the same intensity.
The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
<h3>What is Enthalpy of Fusion ?</h3>
The amount of energy needed to change 1 mole of substance under state change at constant temperature and pressure is called enthalpy of fusion. It is also known as Latent heat of fusion. Unit of enthalpy of fusion is kJ/mol.
<h3>How to find the change in energy ? </h3>
To find the change in energy use this expression:
q = n ΔH
where
q = Energy change
n = number of moles
ΔH = Molar enthalpy
Number of moles (n) =
=
= 0.39 mol
Now put the values in above formula we get
q = n ΔH
= 0.39 mol × 2.29 kJ/mol
= 0.89 kJ
Thus from the above conclusion we can say that The enthalpy of fusion for Hg is 2.29 kJ/mol. 0.89 kJ is the energy change when 78.0 g of Hg melts at −38.8°C.
Learn more about the Latent heat of fusion here: brainly.com/question/87248
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