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kykrilka [37]
4 years ago
6

What is the purpose of the ism/wlan indicator light on the backplane of the router? what does it refer to?

Physics
2 answers:
ikadub [295]4 years ago
4 0
SM/LAN which would demonstrate that there is a Cisco Internal Services Module or a remote LAN card. LAN interfaces the PC equipment in a confined territory, for example, an office or home. Normally, LANs utilize wired associations with connect the PCs to each other and to an assortment of fringe gadgets, for example, printers. LAN clients can speak with each other by talk or email.
sweet-ann [11.9K]4 years ago
4 0
The purpose of the ISM/WLAN indicator light on the back plane of the router is The Cisco 1941 router can support a Cisco Internal Services Module that can enhance the intelligence and abilities of the router to perform activities like intrusion prevention scanning. The Cisco 1941 router can be also equipped with a WLAN Card or Wireless LAN card for supporting wireless local area networks.
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How does the force of gravity on jupiter compare to the force of gravity on earth?
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A small box slides down a ramp on a friction with surface. If the total energy of the system is conserved, which computational m
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A 75 kg bungee jumper leaps from a bridge. When he is 30 meters above the water, and moving at a speed of 20 m/s, the bungee cor
jasenka [17]

Answer:

k = 52.2 N / m

Explanation:

For this exercise we are going to use the conservation of mechanical energy.

Starting point. When it is 30 m high

        Em₀ = K + U = ½ m v² + m g h

Final point. Right when you hit the water

        Em_{f} = K_{e} = ½ k x²

in this case the distance the bungee is stretched is 30 m

        x = h

as they indicate that there are no losses, energy is conserved

        Em₀ = Em_{f}

       ½ m v² + m g h = ½ k h²

       k = \frac{m (v^{2} + 2 g h)}{h^{2} }

let's calculate

       k = \frac{75 \ ( 20^{2}  + 2 \ 9.8 \ 30)}{30^{2} }

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3 0
3 years ago
A particle with an initial linear momentum of 2.00 kg-m/s directed along the positive x-axis collides with asecond particle, whi
Anna11 [10]

Answer:

Explanation:

We shall apply conservation of momentum along x and y axis.

Let the final momentum of second particle be p₁ along x axis and p₂ along y axis.

Considering momentum along x axis

2 + 0 = 3 cos 45 + p₁

p₁ = 2-2.12 = - 0.12 kg m/s

Considering momentum along y axis

4 + 0 = 3 sin 45 + p₂

p₂ = 4-2.12 = 1.88  kg m/s

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=√ ( .12² + 1.88² )

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3 years ago
A man cleaning his apartment pushes a vacuum cleaner with a force of magnitude 84.5 N. The force makes an angle of 33.9 ◦ with t
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Answer:

183.75641 Joules

Explanation:

F = Force of the vacuum cleaner = 84.5 N

s = Displacement of the vacuum cleaner = 2.62 m

\theta = Angle the force makes with the horizontal = 33.9°

Work done is given by

W=F\times scos\theta\\\Rightarrow W=84.5\times 2.62\times cos33.9\\\Rightarrow W=183.75641\ J

The work done by the force of the vacuum cleaner is 183.75641 Joules

6 0
3 years ago
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