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3 years ago

You indicate that a symbol

Physics

1 answer:

Goryan [66]3 years ago

8 0

Answer:

B. over the symbol.

Explanation:

vectors are represented with a symbol carrying an arrow head with also indicates direction

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Vlada [557]

Answer:

2. Move faster

Explanation:

Because you lighten the weight and pushed at the same speed it is easier to push the 400-grams than the 800-grams.

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3 years ago

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In an arcade game, a 0.126 kg disk is shot across a frictionless horizontal surface by compressing it against a spring and relea

bearhunter [10]

Answer:

4.156 m/s

Explanation:

See attachment

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3 years ago

An electric motor consumes 9.00 kj of electrical energy in 1.00 min. if one-third of this energy goes into heat and other forms

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3 years ago

A student was traveling to see his grandmother who lives 15 miles north oh his home he started from rest and maintained a pace o

N76 [4]

Explanation:

Given parameters:

Distance = 15miles north = 24140.2m

Initial velocity = 0m/s

Final velocity = 4m/s

Unknown:

Speed, velocity and acceleration = ?

Solution:

The speed is the distance divide by time. It is a scalar quantity and has no directional attribute.

Speed = $\frac{distance }{time}$

The speed of the student is 4m/s

Velocity is the displacement divided by time. It is a vector quantity which specifies the direction and magnitude;

Velocity = $\frac{displacement}{time}$

The velocity of the student is 4m/s due north

Acceleration is the change in velocity with time;

To find the acceleration, we use

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

4² = 0² + 2x a x 24140.2

a = $\frac{16}{2 x 24140.2}$ = 0.00033m/s²

3 0

3 years ago

A 650-kg elevator starts from rest. It moves upward for 3.00 s with constant acceleration until it reaches its cruis- ing speed

Nataly_w [17]

Answer: $P=5573.43\ W$

Explanation:

Given

Mass of the elevator is $M=650\ kg\\\$

Time period of ascension $t=3\ s$

cruising speed $v=1.75\ m/s$

Distance moved by elevator during this time

Suppose Elevator starts from rest

$\Rightarrow v=u+at\\\Rightarrow 1.75=0+a(3)\\\Rightarrow a=0.583\ s$

Distance moved

$\Rightarrow h=ut+0.5at^2\\\Rightarrow h=0+0.5\times 0.5833\times (3)^2\\\Rightarrow h=2.62\ m$

Gain in Potential Energy is

$\Rightarrow E=mgh\\\Rightarrow E=650\times 9.8\times 2.62\\\Rightarrow E=16,720.3\ N$

Average power during this period is

$\Rightarrow P=\dfrac{E}{t}\\\\\Rightarrow P=\dfrac{16,720.3}{3}\\\\\Rightarrow P=5573.43\ W$

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3 years ago

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