Answer:
88.2 C
Explanation:
The current can be defined as the rate of flow of charge in a conductor.
The relation between charge current and time is given as
I = Q/T
I = current, Q= charge and T = time
that is ampere = coulomb / second
The amount of charge passed is from the negative to the positive terminal
shall be given by:
Q = I * t = 3.5mA * 7h * 3600s/h = 88.2 C
Note: take care of the units.
Answer:
mass is lifted 1.8 m. What is the potential energy of the mass 4. A 100 kg
Answer:
7.45 s.
Explanation:
Given:
h = 68.1 m
vi = 0 m/s
vf = 42.4 m/s
g = 9.81 m/s^2
Using,
h = vi*t +1/2*(a*t^2)
68.1 = 1/2 * (9.81*t^2)
t = sqrt((68.1*2)/9.81)
= 3.726 s.
Total time of flight = 2*t
= 2 * 3.726
= 7.45 s.
Answer:
4000J
Explanation:
Given parameters:
Weight of the man = 800N
Height of ladder = 5m
Unknown:
Gravitational potential energy gained = ?
Solution:
The gravitational potential energy is due to the position of a body.
Gravitational potential energy = weight x height
Now insert the parameters;
Gravitational potential energy = 800 x 5 = 4000J
As per above given data
initial velocity = 19.3 km/s
final velocity = - 18.8 km/s
now in order to find the change in velocity
![\Delta v = v_f - v_i](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20v_f%20-%20v_i)
![\Delta v = -18.8 - 19.3](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-18.8%20-%2019.3)
![\Delta v = -38.1 km/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-38.1%20km%2Fs)
![\Delta v = -3.81 * 10^4 m/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20-3.81%20%2A%2010%5E4%20m%2Fs)
Part b)
Now we need to find acceleration
acceleration is given by formula
![a = \frac{\Delta v}{\Delta t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D)
given that
![\Delta v =- 3.81 * 10^4 m/s](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D-%203.81%20%2A%2010%5E4%20m%2Fs)
![\Delta t = 2.07 years = 6.53 * 10^7 s](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%202.07%20years%20%3D%206.53%20%2A%2010%5E7%20s)
now the acceleration is given as
![a = \frac{-3.81 * 10^4}{6.53 * 10^7}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B-3.81%20%2A%2010%5E4%7D%7B6.53%20%2A%2010%5E7%7D)
![a = - 5.84 * 10^{-4}m/s^2](https://tex.z-dn.net/?f=a%20%3D%20-%205.84%20%2A%2010%5E%7B-4%7Dm%2Fs%5E2)
so above is the acceleration