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3 years ago

A 7.2 kg bowling ball is accelerated with a force of 112,5 N.

Physics

1 answer:

Dominik [7]3 years ago

6 0

Answer:

15.625 m/s

Explanation:

112.5/7.2 = 15.625 m/s

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Answer:

compared to the incident angle, the refracted angle is 45.56⁰

Explanation:

From Snell's law;

n₁sin(I) = n₂sin(r)

Where;

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n₂ is the refractive index of light in medium 2 = 1.4

I is the incident angle

r is the refractive angle

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Applying snell's law

$n_1sin(I) = n_2sin(r)\\\\sin(r) = \frac{n_1sin(I) }{n_2}\\\\sin(r) = \frac{1.2*sin(56.439) }{1.4}\\\\sin(r) = 0.714\\\\r = sin^-(0.714)\\\\r = 45.56^o$

Therefore, compared to the incident angle, the refracted angle is 45.56⁰

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