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yulyashka [42]
3 years ago
8

K + Cl2 -> KCI Balance equation

Chemistry
1 answer:
PtichkaEL [24]3 years ago
7 0

Answer:

2K + Cl2 -> 2KCl

Explanation:

Just balancing :3

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How does the understanding of the structure of the atom help you see both unity and diversity in forms of matter?
gtnhenbr [62]
<span>How does understanding the structure of the atom help you see both unity and diversity in forms of matter?</span><span>


Understanding the structure of the atom helps to understand unity in matter because all matter is made up of those very similar atoms. Understanding the structure of the atom helps to understand diversity in matter because matter can be different (solid, liquid, gas, hard, soft, etc) and knowing the structure of the atom can explain these differences.

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5 0
4 years ago
Read 2 more answers
HELP - a solution NaOCl was prepared at pH 10.3. calculate the concentration of the salt formed. Given Ka for HOCl=3.0x10^-8
GenaCL600 [577]
First we dissociate the salt

NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]

note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.

OCl⁻ + H₂O ⇄ OH⁻ + HOCL

<span>Ka for HOCl = 3.0x10^-8, therefore

Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
                       = 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
                       = 3.3 × 10⁻⁷

</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]

convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴

set up equib table

          OCl⁻                + H₂O    ⇄      OH⁻        +           HOCl
  ST     x                                               0                             0
 +Δ    -1.995 × 10⁻⁴                   +1.995 × 10⁻⁴        +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
 EQ:   x -1.995 × 10⁻⁴                 1.995 × 10⁻⁴          1.995 × 10⁻⁴

Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]

The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M

7 0
4 years ago
Gerald's science teacher mixed room temperature samples of hydrochloric acid and sodium hydroxide in a large beaker. The solutio
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3 years ago
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B. 40 times
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