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galben [10]
3 years ago
13

Which bonds break in the reaction shown

Chemistry
2 answers:
ruslelena [56]3 years ago
6 0

Answer:

Explanation:

Option A is correct .. reactants bond breaks and form new bonds to form product

Citrus2011 [14]3 years ago
5 0
It's A the right answer
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How is the kinetic energy of the particles that make up a substance different after it changes state?
Drupady [299]

Answer:

the answers are either a or d

Explanation:

5 0
3 years ago
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In calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the
BartSMP [9]

Answer: The given statement is TRUE.

Explanation:

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

For example for the given equilibrium reaction;

2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)

K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}

Thus the given statement that in calculating the equilibrium constant for a reaction, the coefficients of the chemical equation are used as exponents for the factors in the equilibrium expression is True.

7 0
3 years ago
If 60.2 grams of hg combines completely with 24.0 grams of br to form a compound what is the percent
NikAS [45]

Answer is: the percent composition of Hg in the compound is 71.5%.

Balanced chemical reaction: Hg + Br₂ → HgBr₂.

m(Hg) = 60.2 g; mass of the mercury.

m(Br₂) = 24.0; mass of the bromine.

m(HgBr₂) = m(Hg) + m(Br₂).

m(HgBr₂) = 60.2 g + 24 g.

m(HgBr₂) = 84.2 g; mass of the compound.

ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.

ω(Hg) = 60.2 g ÷ 84.2 g · 100%.

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6 0
4 years ago
Read 2 more answers
Select all that are true
kipiarov [429]
I think it’s B not quite sure ! Sorry
8 0
3 years ago
Chemistry. Will mark Brainly.
kogti [31]

Answer:

c is right

Explanation:

8 0
3 years ago
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