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3 years ago

Which bonds break in the reaction shown

Chemistry

2 answers:

ruslelena [56]3 years ago

6 0

Answer:

Explanation:

Option A is correct .. reactants bond breaks and form new bonds to form product

Citrus2011 [14]3 years ago

5 0

It's A the right answer

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The equilibrium constant, K, for the following reaction is 2.44×10-2 at 518 K: PCl5(g) PCl3(g) + Cl2(g) An equilibrium mixture o

Volgvan

Answer:

[PCl₅] = 0.5646M

[PCl₃] = 0.1174M

[Cl₂] = 0.1174M

Explanation:

In the reaction:

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

K equilibrium is defined as:

The initial moles of each compound when volume is 15.3L are:

PCl₅ = 0.300mol/L×15.3L = 4.59mol

Cl₂ = 8.55x10⁻²mol/L×15.3L = 1.308mol

PCl₃ = 8.55x10⁻²mol/L×15.3L = 1.308mol

At 8.64L, the new concentrations are:

[PCl₅] = 4.59mol / 8.64L = 0.531M

[PCl₃] = 1.308mol / 8.64L = 0.151M

[Cl₂] = 1.308mol / 8.64L = 0.151M

At these conditions, reaction quotient, Q, is:

Q = [0.151M] [0.151M] / [0.531M]

Q = 4.29x10⁻²

As Q > K, <em>the reaction will shift to the left producing more reactant, </em>that means equilibrium concentrations are:

[PCl₅] = 0.531M + X

[PCl₃] = 0.151M - X

[Cl₂] = 0.151M - X

<em>Where X is reaction coordinate.</em>

Replacing in K expression:

2.44x10⁻² = [0.151M - X] [0.151M - X] / [0.531M + X]

1.296x10⁻² + 2.44x10⁻²X = 0.0228 - 0.302X + X²

Solving for X:

X = 0.293 → False solution. Produce negative concentrations

<em>X = 0.0336M → Right solution.</em>

Replacing:

[PCl₅] = 0.531M + 0.0336

[PCl₃] = 0.151M - 0.0336

[Cl₂] = 0.151M - 0.0336

4 0

4 years ago

2FePO, + 3Na S0,

trapecia [35]

26.5 g of Fe₂(SO₄)₃

Explanation:

We have the following chemical reaction:

2 FePO₄ + 3 Na₂SO₄ → Fe₂(SO₄)₃ + 2 Na₃PO₄

number of moles = mass / molecular wight

number of moles of FePO₄ = 20 / 151 = 0.1325 moles

Taking in account the chemical reaction we devise the following reasoning:

if 2 moles of FePO₄ produces 1 mole of Fe₂(SO₄)₃

then 0.1325 moles of FePO₄ produces X moles of Fe₂(SO₄)₃

X = (0.1325 × 1) / 2 = 0.06625 moles of Fe₂(SO₄)₃

mass = number of moles × molecular wight

mass of Fe₂(SO₄)₃ = 0.06625 × 400 = 26.5 g

Learn more about:

number of moles

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#learnwithBrainly

3 0

4 years ago

Be sure to answer all parts. The percent by mass of bicarbonate (HCO3−) in a certain Alka-Seltzer product is 32.5 percent. Calcu

pochemuha

Answer : The volume of $CO_2$ will be, 514.11 ml

Explanation :

The balanced chemical reaction will be,

$HCO_3^-+HCl\rightarrow Cl^-+H_2O+CO_2$

First we have to calculate the mass of $HCO_3^-$ in tablet.

$\text{Mass of }HCO_3^-\text{ in tablet}=32.5\% \times 3.79g=\frac{32.5}{100}\times 3.79g=1.23175g$

Now we have to calculate the moles of $HCO_3^-$ .

Molar mass of $HCO_3^-$ = 1 + 12 + 3(16) = 61 g/mole

$\text{Moles of }HCO_3^-=\frac{\text{Mass of }HCO_3^-}{\text{Molar mass of }HCO_3^-}=\frac{1.23175g}{61g/mole}=0.0202moles$

Now we have to calculate the moles of $CO_2$ .

From the balanced chemical reaction, we conclude that

As, 1 mole of $HCO_3^-$ react to give 1 mole of $CO_2$

So, 0.0202 mole of $HCO_3^-$ react to give 0.0202 mole of $CO_2$

The moles of $CO_2$ = 0.0202 mole

Now we have to calculate the volume of $CO_2$ by using ideal gas equation.

$PV=nRT$

where,

P = pressure of gas = 1.00 atm

V = volume of gas = ?

T = temperature of gas = $37^oC=273+37=310K$

n = number of moles of gas = 0.0202 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get :

$(1.00atm)\times V=0.0202 mole\times (0.0821L.atm/mole.K)\times (310K)$

$V=0.51411L=514.11ml$

Therefore, the volume of $CO_2$ will be, 514.11 ml

6 0

3 years ago

An ice cube tray contains enough water at 22.0 C to make 18 ice cubes that each have a mass of 30.0g. The tray is placed in a fr

zloy xaker [14]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
158 J is required to vapourize 1 g of CF2Cl2
So for 235.kJ we need. 235.76 x 10^3 J/ 158 J = 1492.15g of CF2Cl2 = 1.492 kg of CF2Cl2

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4 years ago

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Which alcahol will behave most like water?
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3 years ago

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