Given two points (x₁,y₁) and (x₂,y₂), the midpoint of the segment will be:
( (x₁+x₂) / 2 , (y₁+y₂)/2 ).
In this case:
J(-3,18)
T(7,-10)
The midpoint will be:
( (-3+7)/2 , (18-10)/2 )=(4/2 , 8/2)=(2, 4).
Answer: the midpoint of segment JT is (2,4)
Answer:
x = 1.71
Step-by-step explanation:
![x^3-20=-15\\x^3=-15+20\\x^3=5\\\sqrt[3]{x^3} =\sqrt[3]{5} \\x=1.71](https://tex.z-dn.net/?f=x%5E3-20%3D-15%5C%5Cx%5E3%3D-15%2B20%5C%5Cx%5E3%3D5%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%20%3D%5Csqrt%5B3%5D%7B5%7D%20%5C%5Cx%3D1.71)
The answer is B. Hard to explain but it is B.
9.1/3575
use long division like this
_<u>0.</u>_________
3575|91.000000
we find how many of 3575 fit into the 91
it's too big so we go farther
how many 3575 go into 910
too big so we go farther
how many 3575 go into 9100
the answer is 2 so put that in the correct place and mulitply that and put that in the correct place. then we subtract
_<u>0.</u><u>02</u>_________
3575|91.000000
-<u>71.50</u>
19.50
bring down the next number
find how many go into 19.500
the answe ris 5
_<u>0.</u><u>02</u><u>5</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.625
bring down he next zero ( I fast forward and skip steps for convinience)
__
_<u>0.</u><u>02</u><u>5</u><u>455</u>_________
3575|91.000000
-<u>71.50</u>
19.500
-<u>17.875</u>
1.6250
-<u>1.4300</u>
.19500
-<u>.17875
</u> 16250
-14300
and so on untill infinity so the answe ris 0.0254555555555555 (enless fives)
Ur answer will be - A≈69.65cm².
<u><em>Hope this helps!!</em></u>
