Answer:
Let P(t) = population t years after 2010
= 45230e0.02t
Population in 2030 = P(20)
= 45230e0.4≈ 6747
Start by solving one equation for x or y, this time I'm choosing x. 2x = 4 - 2y, then x = 2 - y. Now substitute in x in the other equation. 4(2-y) - 3y = 15. This simplifies to 8 - 4y - 3y = 15. This simplifies to -7y = 7. Divide both sides by -7, and y = -1. Now plug the y value into the other equation: 2x + 2(-1) = 4. This simplifies to 2x = 6, and x = 3.
X = 3, Y = -1 or (3,-1)
"<span>9 1/4 ounces of fertilizer, 3/4 ounce of fertilizer for each plant."
Divide the total amt. of fert. by the amt. that goes to each plant:
9 1/4 oz
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(3/4) oz per plant
Convert 9 1/4 to an improper fraction: 9 1/4 = 37/4.
Now divide 37/4 by 3/4, or divide 37 by 3. Result: 12 1/3 plants.
Ms. Marks can fertilize 12 plants and have 1/3 oz of fertilizer left over.</span>