The craft is moving at a **speed** of v = 0.024c or around 7 million metres per** second** or 16 million miles per hour.

The time dilation factor is equal to 3600/3599 if we only want 3599 **seconds **of the craft's time to pass for every hour (3600 **seconds**) of Earth time. However, there is a connection as well.

**γ** = = Dilation factor

Also, **γ** = 1/ √/

which we can solve algebrically to yield,

= √1-1/**γ**

we get,

= 0.024

v= 0.024c

Accordingly, the craft is moving at a **speed** of v = 0.024c, or around 7 million metres per second or 16 million miles per hour.

Learn more about **speed **of craft here;

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The airplane engine uses oxygen from the air to keep the engines working. Rockets must carry their oxygen for the engines to operate. Third Law of Motion). Rocket propellants by combustion provide the hot gas es that produce reaction force (thrust) when ejected to the rear.

**Answer:**

The maximum mass is

**Explanation:**

The wavelength of the electron can be determined by means of the De Broglie equation.

** (1)**

Where h is the Planck's constant and p is the momentum.

**(2)**

Where m is the mass and v is the velocity.

Before using equation 2 it is necessary to express the wavelength from femtometers to meters.

--

Finally, equation 2 can be used.

But

Hence, the maximum mass is

**Answer:**

**Explanation:**

First of all, we have to find the power used by the hair dryer, which is given by

where

V = 120 V is the voltage

is the resistance of the hair dryer

Substituting,

Now we can find the total electrical energy used, given by

where P is the power and

t = 2.5 min = 150 s is the time

Substituting,

**Answer:**

a) v = 18.86 m / s, b) h = 8.85 m

**Explanation:**

a) For this exercise we can use the conservation of energy relations.

Starting point. Like the compressed spring

Em₀ = K_e + U = ½ k x² + m g x

the zero of the datum is placed at the point of the uncompressed spring

Final point. With the spring if compress

Em_f = K = ½ m v²

how energy is conserved

Em₀ = Em_f

½ k x² + m g x = ½ m v²

v² = x² + 2gx

let's reduce the magnitudes to the SI system

m = 500 g = 0.500 kg

x = -45 cm = -0.45 m

the negative sign is because the distance in below zero of the reference frame

let's calculate

v² = 0.45² + 2 9.8 (- 0.45)

v = √355.68

v = 18.86 m / s

b) For this part we use the conservation of energy with the same initial point and as an end point at the point where the rock stops

Em_f = U = m g h

Em₀ = Em_f

½ k x²2 + m g x = m g h

h = ½ x² + x

let's calculate

h = - 0.45

h = 8.85 m

measured from the point where the spring is uncompressed