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Arada [10]
3 years ago
13

C

Physics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

27J  

3528J

Explanation:

First problem:

Given parameters:

Mass of tennis ball  = 0.06kg

Velocity of tennis ball  = 30m/s

Unknown:

Kinetic energy  = ?

Solution:

Kinetic energy is the energy due to the motion of a body.

It is expressed as:

       K.E  = \frac{1}{2} m v²  

       K.E =  \frac{1}{2}  x 0.06 x 30²   = 27J  

Second problem:

Given parameters:

Mass = 30kg

Height  = 12m

Unknown:

Potential energy  = ?

Solution:

Potential energy is the energy due to the position of a body.

  Mathematically;

       Potential energy  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

 Now;

          Potential energy  = 30 x 9.8 x 12  = 3528J

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Answer:

B) x^2+6x+8

Explanation:

x-4 | x^3+2x^2-16x-32

    -  x^3-4x^2             <-- (x-4)(x^2)

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              6x^2-16x-32

           -  6x^2-24x     <-- (x-4)(6x)

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This means the answer is B) x^2+6x+8

             

3 0
3 years ago
A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy
11Alexandr11 [23.1K]
Given a = 10 cm/s²
          u = 0 cm/s
          v = 50 cm/s
we know that 
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        2500=2×10×S
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8 0
3 years ago
(8c8p49) A 115g Frisbee is thrown from a point 1.00 m above the ground with a speed of 12.00 m/s. When it has reached a height o
IgorLugansk [536]

Answer:

The work done on the Frisbee is 1.36 J.

Explanation:

Given that,

Mass of Frisbee, m = 115 g = 0.115 kg

Initial speed of Frisbee, u = 12 m/s at a point 1 m above the ground

Final speed of Frisbee , v = 10.9674 m/s when it has reached a height of 2.00 m. Let W is the work done on the Frisbee by its weight. According to work energy theorem, the work done is equal to the change in its kinetic energy. So,

W=\dfrac{1}{2}m(v^2-u^2)\\\\W=\dfrac{1}{2}\times0.115\times\left((10.9674)^{2}-(12)^{2})\right)\\\\W=-1.36\ J

So, the work done on the Frisbee is 1.36 J. Hence, this is the required solution.

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