Answer:c will be answer
Explanation:Because u know F=ma so if we wanna know m then we should move a on left side and it will be in divide with f after moving on left side so
M=F/A
Answer:
ω = √(2T / (mL))
Explanation:
(a) Draw a free body diagram of the mass. There are two tension forces, one pulling down and left, the other pulling down and right.
The x-components of the tension forces cancel each other out, so the net force is in the y direction:
∑F = -2T sin θ, where θ is the angle from the horizontal.
For small angles, sin θ ≈ tan θ.
∑F = -2T tan θ
∑F = -2T (Δy / L)
(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m). (This is derived by solving a second order differential equation.)
In this case, k = 2T/L, so the frequency is:
ω = √((2T/L) / m)
ω = √(2T / (mL))
Answer:
a. you speak clearly and well
Explanation:
The magnetic force between two wires is 0.052 N which is attract each other.
We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is
F = μ₀ . I1 . I2 . L / ( 2π . r )
where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.
From the question above, we know that:
L = 25 m
r = 6 cm
I1 = I2 = 25 A
By substituting the parameter, we get
F = μ₀ . I1 . I2 . L / ( 2π . r )
F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)
F = 0.052 N
Hence, the force between two wires is 0.052 N which is attract each other.
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Answer:
Explanation:
Given
-- radius of hydrogen atom
<em>See attachment</em>
Required
Determine the radius of magnesium atom (R)
From the attachment, the ratio of a hydrogen atom to a magnesium atom is:
Simplify
Represent the radius as ratio:
Substitute
Equate both ratios
Express as fraction
Cross Multiply
Hence, the radius of the magnesium atom is: 
