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Maurinko [17]
3 years ago
5

HELP ASAP!! WILL TRY TO GIVE BRAINLIEST

Physics
1 answer:
poizon [28]3 years ago
5 0

Explanation:

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A 3000-N force gives an object an acceleration of 15m/s^2 the mass of the object is?
Shkiper50 [21]

Answer:c will be answer

Explanation:Because u know F=ma so if we wanna know m then we should move a on left side and it will be in divide with f after moving on left side so

M=F/A

7 0
3 years ago
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On a horizontal frictionless surface a mass M is attached to two light elastic strings both having length l and both made of the
EastWind [94]

Answer:

ω = √(2T / (mL))

Explanation:

(a) Draw a free body diagram of the mass.  There are two tension forces, one pulling down and left, the other pulling down and right.

The x-components of the tension forces cancel each other out, so the net force is in the y direction:

∑F = -2T sin θ, where θ is the angle from the horizontal.

For small angles, sin θ ≈ tan θ.

∑F = -2T tan θ

∑F = -2T (Δy / L)

(b) For a spring, the restoring force is F = -kx, and the frequency is ω = √(k/m).  (This is derived by solving a second order differential equation.)

In this case, k = 2T/L, so the frequency is:

ω = √((2T/L) / m)

ω = √(2T / (mL))

6 0
4 years ago
Fluency means that
dalvyx [7]

Answer:

a. you speak clearly and well

Explanation:

6 0
3 years ago
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Determine the magnitude and direction of the force between two parallel wires 25 m long and 6.0 cm apart, each carrying 25 a in
mr Goodwill [35]

The magnetic force between two wires is 0.052 N which is  attract each other.

We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is

F = μ₀ . I1 . I2 . L / ( 2π . r )

where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.

From the question above, we know that:

L = 25 m

r = 6 cm

I1 = I2 = 25 A

By substituting the parameter, we get

F = μ₀ . I1 . I2 . L / ( 2π . r )

F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)

F = 0.052 N

Hence, the force between two wires is 0.052 N which is  attract each other.

Find more on magnetic force at: brainly.com/question/13277365

#SPJ4

7 0
2 years ago
A hydrogen atom has a radius of 2.5 x 10-11 m<br> Determine the radius of a magnesium atom.
baherus [9]

Answer:

R = 1.5* 10^{-10}m

Explanation:

Given

r = 2.5 * 10^{-11}m -- radius of hydrogen atom

<em>See attachment</em>

Required

Determine the radius of magnesium atom (R)

From the attachment, the ratio of a hydrogen atom to a magnesium atom is:

Ratio = 6mm : 36mm

Simplify

Ratio =1 : 6

Represent the radius as ratio:

Ratio = r : R

Substitute r = 2.5 * 10^{-11}m

Ratio = 2.5 * 10^{-11}m : R

Equate both ratios

2.5 * 10^{-11}m : R = 1 : 6

Express as fraction

\frac{2.5 * 10^{-11}m}{R} = \frac{1}{6}

Cross Multiply

R * 1 = 2.5 * 10^{-11}m * 6

R * 1 = 2.5 * 6* 10^{-11}m

R * 1 = 15* 10^{-11}m

R = 15* 10^{-11}m

R = 1.5*10* 10^{-11}m

R = 1.5* 10^{1-11}m

R = 1.5* 10^{-10}m

Hence, the radius of the magnesium atom is: 1.5* 10^{-10}m

6 0
3 years ago
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