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2 years ago

Newton's laws of motion

Physics

2 answers:

Kipish [7]2 years ago

8 0

Answer:second law

Acceleration of an object depends on the mass of the object and the amount of force applied

Strike441 [17]2 years ago

4 0

It’s newton’s 2nd law of motion

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Se necesita subir una carga de 500 kg (4900 N) a una altura de 1.5 m deslizándola sobre una rampa inclinada. ¿Qué longitud debe

marusya05 [52]

Answer:

4.22 m

Explanation:

Una rampa es una máquina que se utiliza para levantar un objeto con una fuerza menor a la que realmente necesitarías. Cuanto mayor sea la longitud de la rampa, menor será la magnitud de la fuerza necesaria para levantar el objeto.

Dado que:

altura de la rampa = 1.5 m, carga = 4900 N, fuerza aplicada = 1633.33 N.

La fórmula de la rampa se da como:

fuerza aplicada * longitud de la rampa = peso de la carga * altura de la rampa

1633.33 * longitud de la rampa = 4900 * 1.5

longitud de la rampa = 4900 * 1.5 / 1633.33

longitud de la rampa = 4.22 m

6 0

3 years ago

Find the magnitude of the sum

shusha [124]

Answer:

$\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m$

Explanation:

<u>Sum of Vectors in the Plane</u>

Given two vectors

$\displaystyle \vec{v_1}\ ,\ \vec{v_2}$

They can be expressed in their rectangular components as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_2}=$

The sum of both vectors can be done by adding individually its components

$\displaystyle \vec{v_1}+\vec{v_2}=$

If the vectors are given as a magnitude and an angle $(M\ ,\ \theta )$ , each component can be found as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_2}=$

The first vector has a magnitude of 3.14 m and an angle of 30°, so

$\displaystyle \vec{v_1}=$

The second vector has a magnitude of 2.71 m and an angle of -60°, so

$\displaystyle \vec{v_2}=$

The sum of the vectors is

$\displaystyle \vec{v_1}+\vec{v_2}=$

$\displaystyle \vec{v_1}-\vec{v_2}=$

Finally, we compute the magnitude of the sum

$\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{(4.08)^2+(-0.78)^2}$

$\displaystyle |\vec{v_1}+\vec{v_2}|=\sqrt{17.25}$

$\displaystyle |\vec{v_1}+\vec{v_2}|=4.15m$

3 0

2 years ago

A helicopter flies 168 miles against the wind in 2 hours; with the wind, it can fly 252 miles in the same amount of time. find t

posledela

Let $v_h$ be the speed of the helicopter in still air. Let $v_w$ be the speed of the wind. Then, from the given information,

$(v_h-v_w)2=168\\ (v_h+v_w)2=252\\$

Adding the above 2 equations,

$4v_h=168+252\\ 4v_h=420\\ v_h=105$

The speed of the helicopter in still air $105 \;mi/hour$

6 0

3 years ago

Read 2 more answers

If a dog runs at 3 m/s for 20 seconds, how far did he run

prisoha [69]

60 meters

20 x 3 =60

Brainliest?

3 0

3 years ago

Read 2 more answers

A uniform cylindrical grindstone has a mass of 15.0 kg and a radius of 18.6 cm. The grindstone reaches a rotational velocity of

tekilochka [14]

Answer:

$n \approx 5.778\times 10^{-4}\,rev$

Explanation:

The Work-Energy Theorem is applied herein:

$-\frac{1}{4}\cdot m_{cyl}\cdot R^{2}\cdot \omega^{2} = - \mu_{k}\cdot N\cdot r \cdot 2\pi \cdot n$

The number of turns needed to stop the grindstone is:

$n = \frac{m_{cyl}\cdot R^{2}\cdot \omega^{2}}{4\cdot \mu_{k}\cdot N \cdot r\cdot 2\pi}$

$n = \frac{(15\,kg)\cdot (0.186\,m)^{2}\cdot [(1.83\,\frac{rev}{min} )\cdot (\frac{2\pi\,rad}{1\,rev} )\cdot (\frac{1\,min}{60\,s} )]^{2}}{4\cdot (0.80)\cdot (8.82\,N)\cdot(0.186\,m)\cdot 2\pi}$

$n \approx 5.778\times 10^{-4}\,rev$

8 0

3 years ago