Answer:
2.4 mole of oxygen will react with 2.4 moles of hydrogen
Explanation:
As we know
1 liter = 1000 grams
2H2 + O2 --> 2H2O
Weight of H2 molecule = 2.016 g/mol
Weight of water = 18.01 gram /l
2 mole of oxygen react with 2 mole of H2
2.4 mole of oxygen will react with 2.4 moles of hydrogen
Answer:
A. Engineers come up with scientific questions when they are developing their design, and scientists do research to answer them.
Equation of decomposition of ammonia:
N2+3H2->2NH3
Euilibrium constant:
Kc=(NH3)^2/((N2)((H2)^3))
As concentration of N2=0.000105, H2=0.0000542
so equation will become:
3.7=(NH3)^2/(0.000105)*(0.0000542)^3
NH3=√(3.7*0.000105*(0.0000542)^3)
NH3=7.8×10⁻⁹
So concentration of ammonia will be 7.8×10⁻⁹.
Answer:
3 × 10¯¹⁰
Explanation:
9×10² ÷ 3×10¹²
The above expression can be simplified as follow:
9×10² ÷ 3×10¹²
Recall:
9 = 3²
9×10² ÷ 3×10¹² = 3²×10² ÷ 3×10¹²
Recall:
a^m ÷ a^n = a^(m – n)
3²×10² ÷ 3×10¹² = 3^(2 – 1) × 10^(2 – 12)
= 3¹ × 10¯¹⁰
Recall:
a¹ = a
3¹ × 10¯¹⁰ = 3 × 10¯¹⁰
Answer:
it is organism the third one
