Iron-58 how many protons electrons and neutrons ?

What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃ + 3H₂ → 3H₂O + W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194 .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0

2 years ago

What is the relationship between the atomic mass of a substance and its molar mass?

sdas [7]

The relationship is that atomic mass is used to calculate molar mass
Example: H2O
2(1.007) + 15.999
18.013

3 0

1 year ago

An unknown organic compound composed of carbon, hydrogen, and oxygen was analyzed and found to be 50.84% C, 8.53% H, and the res

MariettaO [177]

In every 100g of that compund there is 50.84 g of C, 8.53 g H and (100-59.37) g = 40.63 g of O.

Step 1: Convert each element's mass in moles. To do that we need to divide each element's mass by their respective molar mass.

For Carbon.

$C = \frac{50.84}{12} = 4.24 mol$

For Hydrogen.

$H = \frac{8.53}{1} = 8.53 mol$

For Oxygen.

$O = \frac{40.63}{16} = 2.54 mol$

Step 2: Divide each of the numbers by the smallest number.

For Carbon.

$C = \frac{4.24}{2.54} = 1.7$

For Hydrogen.

$H = \frac{8.53}{2.54} = 3.36$

For Oxygen.

$O = \frac{2.54}{2.54} = 1$

Step 3: So the empirical formula will be.

$C_{1.7} H_{3.36} O_1$

But using decimal will be messy. So we multiply the numbers by 3. The right empirical formula will be.

$C_{5} H_{10} O_3$

7 0

3 years ago

What information is presented inside each square of the periodic table?

Verdich [7]

The symbol, the atomic mass, the number of protons and electrons

8 0

3 years ago

The "d" subshell can hold a maximum of ________ electrons.

Verizon [17]

The d subshell has 5 orbitals (with each being able to hold two electrons. As such, the d orbital can hold a maximum of 10 electrons.

<span>The "d" subshell can hold a maximum of _TEN_ electrons.</span>

5 0

2 years ago