Answer:
my answer is B
Step-by-step explanation:
hope this helps
Answer:
9
Step-by-step explanation:
So there's 3 1's, 2 2's, 2 3's, 1 4, 2 5's, a 6, a 7, an 8, 2 0's, and no 9's.
Answer:
....
Step-by-step explanation:
....
Here is a note: the sum of the 2 shorter sides have to be greater than the longest side. Sorry that i cant help more.
I guess you are asking to find the sum of the first 8 terms. If so, then:
Sum = a₁(1-rⁿ)/(1-r), where a₁ is the 1st term, r=common ratio and n=number of terms:
the 1st term a₁ =3
common ratio r = - 2 (since -6/3 = - 2, and 12/-6 = - 2, etc.)
Sum = 3[(1- (-2)⁸]/(1-2) = 3(1- 256)/(1/2)
Sum = -1530
