Answer:
0.375 M
Explanation:
NaOH(aq) + HBr(aq) ------------> NaBr(aq) + H2O(l)
Concetration of acid CA= 0.250M
Concentration of base CB= ????
Volume of acid VA= 30.0mL
Volume of base VB= 20.0mL
Number of moles of acid nA= 1
Number of moles of base nB= 1
CA VA/CB VB= nA/nB
CB= CAVAnB/VB nA
= 0.25× 30×1/20×1= 0.375 M
<u>Answer:</u> The moles of water produced are 1.54 moles.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of ethane = 15.42 g
Molar mass of ethane = 30.07 g/mol
Putting values in above equation, we get:
The chemical equation for the combustion of ethane follows:
By Stoichiometry of the reaction:
2 moles of ethane produces 6 moles of water
So, 0.513 moles of ethane will produce = 
of water
Hence, the moles of water produced are 1.54 moles.
Your answer will be False cladistics are use to tie an animal to its ancestor.
Assuming that you mean table sugar (sucrose), then at room temperature and without any catalyst, there is no reaction.
However if you elevate and hold the temperature of the aqueous solution at 50 to 60 °C (especially in the presence of a suitable catalyst, like mineral acid) the sucrose dimer will split into glucose and fructose. This is called hydrolysis and the resulting solution is called an invert sugar solution.
The reaction could be written as:
C12H22O11 (sucrose) + H2O (water) → C6H12O6 (glucose) + C6H12O6 (fructose)
or
C12H22O11 (aq) + H2O (l) → C6H12O6 (aq) + C6H12O6 (aq)
Notice that both of the produced sugars have the same empirical formula. Check with your instructor or in your textbook to see if more exact formulas are needed.
