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2 years ago

10

Is there any organism on the food web that could completely die out that would have no impact on other organisms? Why or why not

?

1 answer:

andrew11 [14]2 years ago

4 0

Yes because obviously some other organism lives off eating that organism so if they die off the other organisms will be affected heavily

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based on my knowledge

B. 678.5 j

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2 years ago

What is the chemical formula for ammonium sulfate?

Naya [18.7K]

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3 years ago

Howtocalculatethevolumeofcarbondioxideproducedwhen400gofmarblewereats.t.p<br>

lys-0071 [83]

Answer:

so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.

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3 years ago

Can someone help me? It needs to have a diagram that has arrows.

daser333 [38]

Answer: The enthalpy change for formation of butane is -125 kJ/mol

Explanation:

The balanced chemical reaction is,

$C_4H_{10}(g)+\frac{13}{2}O_2(g)\rightarrow 4CO_2(g)+5H_2O(l)$

The expression for enthalpy change is,

$\Delta H=[n\times H_f{products}]-[n\times H_f{reactants}]$

Putting the values we get :

$\Delta H=[4\times H_f_{CO_2}+5\times H_f_{H_2O}]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times H_f_{O_2}]$

$-2877=[(4\times -393)+(5\times -286)]-[1\times H_f_{C_4H_{10}}+\frac{13}{2}\times 0]$

$H_f_{C_4H_{10}=-125kJ/mol$

Thus enthalpy change for formation of butane is -125 kJ/mol

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3 years ago

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MAVERICK [17]

Answer: kinetic energy

Explanation: I just took that test

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3 years ago