Delta H of solution = -Lattice Energy + Hydration <span>Delta H of solution=- (-730)+(-793) </span> <span>Delta H of solution= -63kJ/mol </span>
<span>Now we find moles of LiI: </span> <span>10gLiI/133.85g=.075moles </span> <span>multiply moles to the delta H of solution to cross cancel moles. .75moles x -64kJ/mol =4.7</span>
