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AfilCa [17]
3 years ago
11

What is the freezing point of glucose?

Chemistry
1 answer:
Triss [41]3 years ago
7 0

Answer:

In Fahrenheit it is 294.8°F and in Celsius it is 146°C.

You might be interested in
Which of the following is an important difference between climate and weather?
ANEK [815]

A

Explanation:

Weather can be defined as the day-to-day changes in the atmospheric parameters like temperatures, humidity,  rainfall, and pressure. When these weather changes are observed for approximately over 30 years, the climate of the regions can be determined by understanding the patterns.

5 0
3 years ago
Physical properties of reactants: Physical properties of products: 12.
dolphi86 [110]

Answer: The reactants are baking soda and vinegar. Baking soda is a white powder, and vinegar is a clear liquid. The products of this reaction are carbon dioxide, water, and sodium acetate. Carbon dioxide is a colorless gas, water is a colorless liquid, and sodium acetate is a white crystalline powder.

A chemical change can be seen in how the molecular formulas of the products are different from the reactants, since the reactants have chemically changed into completely different molecules.

Hope this helps

6 0
3 years ago
If the atmospheric pressure in the laboratory is 1.2 atm, how many moles of gas were in each syringe? (Hint: Choose one volume a
Naily [24]

Answer:

A: 2.525 x 10-4 mol

B: 2.583 x 10-4 mol

Explanation:

Part A:

Data Given:

. Temperature of water (H2O) = 21.3°C

Convert Temperature to Kelvin

T = °C + 273

T = 21.3 + 273 = 294.3 K

volume of (H2O) gaseous state = 5.1 mL

Convert mL to liter

1000 mL = 1L

5.1 ml = 5.1/1000 = 0.0051 L

Pressure = 1.2 atm

. no. of moles = ?

Solution

no. of moles can be calculated by using ideal gas formula

PV = nRT

Rearrange the equation for no. of moles

n=PV/RT......... (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

where

R = 0.08206 L.atm/ mol. K

Now put the value in formula (1) to calculate no. of moles of

n = 1.2 atm x 0.0051 L / 0.08206 L.atm.mol-1. K-1 x 294.3 K

n = 0.0061 atm.L / 24.162 L.atm.mol-1

n = 2.525 x 10-4 mol

no. of moles of gas (H2O) = 2.525 x 10-4 mol

Part B:

Data Given:

Temperature of water (H2) = 21.3°C

Convert Temperature to Kelvin

T = "C + 273

T= 21.3 + 273 = 294.3 K

volume of (H2) gas = 5.2 mL

Convert mL to liter

1000 mL = 1 L

5.2 ml = 5.2/1000 = 0.0052 L

Pressure = 1.2 atm

. no. of moles = ?

Solution

no. of moles can be calculated by using ideal gas formula

PV = nRT

Rearrange the equation for no. of moles

n= PV / RT......... (1)

where

P = pressure

V = Volume

T= Temperature

n = Number of moles

R = ideal gas constant

where

R = 0.08206 L.atm/mol. K

Now put the value in formula (1) to calculate no. of moles of

n = 1.2 atm x 0.0052 L/0.08206 L.atm.mol-1. K-1 x 294.3 K

n = 0.0062 atm.L/ 24.162 L.atm.mol-1

n = 2.583 x 10-4 mol

I

no. of moles of gas (H2) = 2.583 x 10-4 mol

8 0
3 years ago
What mass, in grams, of CO2 and H20 N<br> is formed from 2.55 mol of propane?
Black_prince [1.1K]

Answer: The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

Explanation:

The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.

Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

a) 1 mol of propane produces = 3 moles of CO_2

Thus 2.55 mol of propane produces = \frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2

mass of CO_2=moles\times {\text {molar mass}}=7.65mol\times 44g/mol=336.6g

b) 1 mol of propane produces = 4 moles of H_2O

Thus 2.55 mol of propane produces = \frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O

mass of H_2O=moles\times {\text {molar mass}}=10.2mol\times 18g/mol=183.6g

The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

8 0
3 years ago
A reaction between liquid reactants takes place at - 11.0 degree C in a sealed, evacuated vessel with a measured volume of 45.0
Sati [7]

Explanation:

The given data is as follows.

       T = 11^{o}C = (11 + 273) K = 284 K,     V = 45.0 L

      m = 35 g

As molar mass of chlorine pentafluoride is 130.445 g/mol. Hence, number of moles of chlorine pentafluoride are as follows.

      No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{35 g}{130.445 g/mol}

                             = 0.268 mol

Now, using the ideal gas equation we will find the pressure as follows.

                          PV = nRT

       P \times 45.0 L = 0.268 mol \times 0.082 L atm/mol K \times  284 K

                       P = 0.139 atm

Thus, we can conclude that pressure of chlorine pentafluoride gas in the given reaction vessel after the reaction is 0.139 atm.

4 0
3 years ago
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