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AveGali [126]
2 years ago
14

Pls help me who is good at science!!​

Chemistry
1 answer:
djverab [1.8K]2 years ago
6 0

Answer: photosynthesis , pollination, decomposition

Explanation:

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CHEMISTRY HELP!
Nostrana [21]

Answer:

A

Explanation:

Arsenic is in the same group as Nitrogen - group 5. They all have 5 valence electrons in their outermost shell. To achieve its most stable state - 8 valence electrons (octet rule - elements are most stable when the entire shell is filled) - arsenic needs to gain 3 electrons. Since electrons have a negative charge, the charge of an As ion would be -3.

Try observing the periodic table and how many valence electrons that each element has. From there, you can determine the charges of the elements lithium and strontium. You can guess, I'll help you with those once you attempt to find the charge of those ions.

4 0
2 years ago
Please help me with this!
GuDViN [60]

Answer:

3.01x10^23

Explanation:

In order to determine the amount of molecules, you have to use Avogadro's number which = 6.02x10^23. To calculate this, multiply the number of moles with Avogadro's number to get the above answer.

Hope this helps!

3 0
2 years ago
At what temperature, in Celsius, will 88.0 g of Ne exert a pressure of 350. kPa in a
bezimeni [28]

Answer:

191 °C

Explanation:

We'll begin by calculating the number of mole in 88.0 g of Ne. This can be obtained as follow;

Mass of Ne = 88.0 g

Molar mass of Ne = 20 g/mol

Mole of Ne =?

Mole = mass /molar mass

Mole of Ne = 88 / 20

Mole of Ne = 4.4 moles

Next, we shall determine the temperature. This can be obtained as follow:

Mole of Ne = 4.4 moles

Pressure (P) = 350 KPa

Volume (V) = 48.5 L

Gas constant (R) = 8.314 KPa.L/Kmol

Temperature (T) =?

PV = nRT

350 × 48.5 = 4.4 × 8.314 × T

16975 = 36.5816 × T

Divide both side by 36.5816

T = 16975 / 36.5816

T = 464 K

Finally, we shall convert 464 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

T(K) = 464 K

T(°C) = 464 – 273

T(°C) = 191 °C

Thus, the temperature is 191 °C

8 0
2 years ago
What mass of silver chloride (m = 143.4) will dissolve in 1.00 l of water? the ksp of agcl is 1.8 × 10–10 ?
trapecia [35]
Given that solubility product of AgCl = 1.8 X 10^-10

Dissociation of AgCl can be represented as follows,

AgCl(s)             ↔      Ag+(ag)             +           Cl-(aq)

Let, [Ag+] = [Cl-] = S

∴Ksp = [Ag+][Cl-] = S^2

∴ S = √Ksp = √(1.8 X 10^-10) = 1.34 x 10^-5 mol/dm3

Now, Molarity of solution = \frac{\text{weight of solute}}{\text{Molecular weight X volume of solution (l)}}
              ∴  1.34 x 10^-5     = \frac{\text{weight of AgCl}}{143.4 X 1}
∴ Weight of AgCl present in solution = 1.92 X 10^-3 g

Thus, mass of AgCl that will dissolve in 1l water = 1.92 x 10^-3 g
7 0
2 years ago
What information does the percent composition of an atom in a molecule<br> give?
Roman55 [17]

Answer:

percent composition tells that by mass

6 0
3 years ago
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