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Anastasy [175]
2 years ago
13

A mixture of CuSO4 · 5H2O and MgSO4 · 7H2O is heated until all the water is lost. If 5.127 g of the mixture gives 2.817 g of the

anhydrous salts, what is the percent by mass of CuSO4 · 5H2O in the mixture?
Chemistry
1 answer:
Nadusha1986 [10]2 years ago
3 0

Answer:

Let the mixture is X% by mass of CuSO

4

.5H

2

O and 100 - X % by mass of MgSO

4

.7H

2

O. 5.0 g of mixture will contain 0.05X g CuSO

4

.5H

2

O and 5.0 - 0.05X g MgSO

4

.7H

2

O

The molar masses of CuSO

4

.5H

2

O and MgSO

4

.7H

2

O are 249.7 g/mol and 246.5 g/mol respectively.

The number of moles of CuSO

4

.5H

2

O=

249.7

0.05X

=2.00×10

−4

X moles.

Explanation:

Pls mark it as branliest answere thanks

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6. A solution of CuSO4 is electrolyzed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the
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<h3>Further explanation</h3>

Given

time = t = 10 min=600 s

current = i = 1.5 A

F = 96500 C

charge Cu=+2

Required

The mass of Copper

Solution

Faraday's Law

\tt W=\dfrac{e.i.t}{96500}

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Input the value :

\tt W=\dfrac{63.5/2\times 1.5\times 600}{96500}\\\\W=0.296~g

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