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sergiy2304 [10]
2 years ago
10

What is a thermal insulation material that is no longer used because of formaldehyde gas emission?

Chemistry
1 answer:
Ludmilka [50]2 years ago
7 0

Urea Formaldehyde Foam Insulation is the thermal insulation material that is no longer used because of formaldehyde gas emission

Urea Formaldehyde Foam Insulation is mixture of urea formaldehyde resin, foaming acid agent, and a propellant used in the 1970s for insulating purposes.

It was specifically designed to insulate the areas of the building that were hard to access. Unlike regular process, it was sprayed into the walls by using holes.

It is no longer used because it caused a raise in the formaldehyde gas in the residence. This gas caused irritations to the people living in the building. Residents started to report health issues like respiratory problems, and eyes, nose, throat irritation.

If you need to learn about the formaldehyde gas, click here.

brainly.com/question/14645797?referrer=searchResults

#SPJ4

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4 years ago
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C + O2 → CO2 ,
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First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
5 0
4 years ago
What is the electron geometry of PF3?
deff fn [24]

Answer:

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Explanation:

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5 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0
3 years ago
What is the number of moles of solute in 250 mL of a 0.4 M solution ?
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.4 M means that in 1 Liter of solution there are .4 moles. 

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250 mL x 1000mL/1 Liter = .25 L

Now, set up the equation

.4 M x .25 L = .1 moles of solute
3 0
3 years ago
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