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torisob [31]
3 years ago
7

Could anyone help me with this ASAP ?

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0

Answer:

Step-by-step explanation:

Ahat [919]3 years ago
3 0

Answer:

Step-by-step explanation:

-3x^4 -9x^3+ 15x^2

-3x^2 ( x^2 + 3x -5)

if you use quadratic formula (see image)

~~~~~~~~~~~~~~~~~~~~~~

10x^3  -35x^2 +6x -21

5x2(2x-7) +3(2x-7)

(5x^{2} + 3) (2x-7)

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Hi. I need help with these questions.<br> See image for question.<br> Answer 14 and 13
irinina [24]

Answer:

  • 13) 36x² + 9x - 4 = 0
  • 14) 21x² + 20x + 100 = 0

Step-by-step explanation:

13.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 4x² - 3x - 4 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of 1/(3α) and 1/(3β)
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -(-3)/4 = 3/4
  • αβ = c/a ⇒ αβ = -4/4 = - 1

<u>New equation is:</u>

  • (x - 1/(3α))(x - 1/(3β)) = 0
  • x² - (1/(3α) + 1/(3αβ))x + 1/(3α3β) = 0
  • x² - ((3α + 3 β)/(3α3β))x + 1/(3α3β) = 0
  • x² - ((α + β)/(3αβ))x + 1/(9αβ) = 0
  • x² - (3/4)/(3(-1))x + 1/(9(-1)) = 0
  • x² + 1/4x - 1/9 = 0
  • 36x² + 9x - 4 = 0

===================

14.

<h3>Given</h3>

<u>Quadratic equation</u>

  • 3x² +2x + 7 = 0
  • With the roots of α and β
<h3>To Find </h3>
  • The quadratic equation with roots of α + 1/β and β + 1/α
<h3>Solution</h3>

<u>The sum and the product of the roots of the given equation:</u>

  • α + β = -b/a ⇒ α + β = -2/3
  • αβ = c/a ⇒ αβ = 7/3

<u>New equation is:</u>

  • (x - (α + 1/β))(x - (β + 1/α)) = 0
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  • x² - (-2/3 - 2/7)x + 7/3 + 3/7 + 2 = 0
  • x² + (14 + 6)/21x + (49 + 9 + 42/21) = 0
  • x² + 20/21x + 100/21 = 0
  • 21x² + 20x + 100 = 0
8 0
3 years ago
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