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2 years ago

Could anyone help me with this ASAP ?

Mathematics

2 answers:

Zigmanuir [339]2 years ago

7 0

Answer:

Step-by-step explanation:

Ahat [919]2 years ago

3 0

Answer:

Step-by-step explanation:

-3x^4 -9x^3+ 15x^2

-3x^2 ( x^2 + 3x -5)

if you use quadratic formula (see image)

~~~~~~~~~~~~~~~~~~~~~~

10x^3 -35x^2 +6x -21

5x2(2x-7) +3(2x-7)

(5 $x^{2}$ + 3) (2x-7)

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2 years ago

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3 years ago

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3 years ago

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Solve by quadratic formula: <br> 8a2 + 6a + 5=0

Veseljchak [2.6K]

Answer:

$x = \frac{-3 \pm i\sqrt{31}}{8}$

Step-by-step explanation:

Quadratic Formula: $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

√-1 is imaginary number i

Step 1: Define Quadratic

8a² + 6a + 5 = 0

a = 8

b = 6

c = 5

Step 2: Plug into Quadratic Formula

$x = \frac{-6 \pm \sqrt{6^2-4(8)(5)} }{2(8)}$

Step 3: Solve

$x = \frac{-6 \pm \sqrt{36-160} }{16}$

$x = \frac{-6 \pm \sqrt{-124} }{16}$

$x = \frac{-6 \pm \sqrt{124} (\sqrt{-1} )}{16}$

$x = \frac{-6 \pm i\sqrt{124}}{16}$

$x = \frac{-6 \pm 2i\sqrt{31}}{16}$

$x = \frac{2(-3 \pm i\sqrt{31})}{16}$

$x = \frac{-3 \pm i\sqrt{31}}{8}$

8 0

3 years ago