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3 years ago

Could anyone help me with this ASAP ?

Mathematics

2 answers:

Zigmanuir [339]3 years ago

7 0

Answer:

Step-by-step explanation:

Ahat [919]3 years ago

3 0

Answer:

Step-by-step explanation:

-3x^4 -9x^3+ 15x^2

-3x^2 ( x^2 + 3x -5)

if you use quadratic formula (see image)

~~~~~~~~~~~~~~~~~~~~~~

10x^3 -35x^2 +6x -21

5x2(2x-7) +3(2x-7)

(5 $x^{2}$ + 3) (2x-7)

You might be interested in

Explain how you would solve 16/c=8. Then solve the equation

Hoochie [10]

$\frac{16}{c} = 8$

16 = c8

c = $\frac{16}{8}$

c = 2

hope this helps!

7 0

3 years ago

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

3 years ago

A cheetah can run at a speed of 60 miles per hour how far can it run in 0.5 hours

damaskus [11]

30 miles
Because you’re cutting the time in half and the same should apply to the speed

4 0

3 years ago

I am in 8th grade and i need help on Pre Algebra could you help me?

Morgarella [4.7K]

Answer:

Sure, what do you need help on?

7 0

3 years ago

Please help me solve this!!

Mice21 [21]

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

$Distance =4\ miles$

$Time = 30\ minutes$

Abelito

$Distance = 10\ miles$

$Time = 48\ minutes$

Required:

Who had a greater average speed

Average speed (S) is calculated as:

$S = \frac{Distance}{Time}$

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

$S_B = \frac{4\ miles}{30\ minutes}$

Convert minute to hour

$S_B = \frac{4\ miles}{0.5\ hr}$

$S_B = 8mph$

For Abelito

$S_A = \frac{10\ miles}{48\ minutes}$

Convert minute to hour

$S_A = \frac{10\ miles}{0.8\ hr}$

$S_A = 12.5mph$

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed

5 0

3 years ago