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grin007 [14]
4 years ago
9

If you install special sound-reflecting windows that reduce the sound intensity level by 33.0 dBdB , by what factor have you red

uced the sound intensity
Engineering
1 answer:
Sever21 [200]4 years ago
3 0

Answer:

The sound intensity is reduced by a factor of 1995.26

Explanation:

When comparing two sound intensities, the intensity level is measured in the unit of decibel or dB. The intensity of the threshold of hearing for a human being is  10^−12 W/m^2 . When the intensity level is zero, it means that the sound intensity is the same as the threshold of hearing.

The reduced sound intensity level is given as 33 dB, so

10  log (I/Io)  = - 33

I  : intensity of the sound

Io ( =   10^−12 W/m^2): threshold of hearing

So, the intensity ratio is

I/Io = 10^-3.3

     = 5.01 x 10^-4

1/ 5.01 x 10^-4 = 1995.26

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Copper is generally considered easy to weld because of its high thermal conductivity: (a) true or (b) false?
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b)False

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8 0
3 years ago
The theoretical maximum specific gravity of a mix at 5.0% binder content is 2.495. Using a binder specific gravity of 1.0, find
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Answer:

The theoretical maximum specific gravity at 6.5% binder content is 2.44.

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Given the specific gravity at 5.0 %  binder content 2.495

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Per 100 mass unit we have (Mx + 5)/(Vx + 5) = 2.495

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3 years ago
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