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3 years ago

The polynomial in standard form that represents the perimeter of the quadrilateral

Mathematics

1 answer:

Naddik [55]3 years ago

6 0

Answer:

3(4x-1)

Step-by-step explanation:

I hope this is correct and helpful

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What is the factored form of x^3 -1

lianna [129]

Answer:

The factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

Step-by-step explanation:

Given the expression

$x^3-1$

Rewrite 1 as 1³

$=x^3-1^3$

$\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)$

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

$=\left(x-1\right)\left(x^2+x+1\right)$

Thus, the factored form of x^3 -1 will be:

$x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

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3 years ago

Algebra Evaluate for the given value for the variable.

VikaD [51]

8 is 7
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4 years ago

Help me please. <br>20+(-16)4

Sphinxa [80]

P.E.M.D.A.S
First , you multiply.

200+(-16)4
200+(-64)

Since they have different signs, you subtract and keep the sign of the greater absolute value.

200+(-64)=136

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3 years ago

Graph and identify image coordinates rx=2

raketka [301]

Answer:

Step-by-step explanation:

Rule defining the reflection across the line x = -2 has been given as,

$r_{x=-2}$

Line x = -2 will work as a mirror for the given triangle J, K, L.

That means distance of the vertices J, K and L and image points J', K' and L' will be equidistant from the line x = -2,

Vertices of the image triangle J'K'L' will be,

J' → (-5, 2)

K' → (-3, 2)

L' → (-4, 1)

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3 years ago

I need serious help with this! I'll give 20 points!

GrogVix [38]

Answer:

glizzy

Step-by-step explanation:

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3 years ago

The polynomial in standard form that represents the perimeter of the quadrilateral ￼￼

The polynomial in standard form that represents the perimeter of the quadrilateral