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denis23 [38]
3 years ago
9

An aqueous solution of calcium hydroxide is standardized by titration with a 0.112 M solution of hydrobromic acid. If 15.2 mL of

base are required to neutralize 12.4 mL of the acid, what is the molarity of the calcium hydroxide solution?
Chemistry
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

0.0457 M

Explanation:

The reaction that takes place is:

  • 2HBr + Ca(OH)₂ → CaBr₂ + 2H₂O

First we<u> calculate how many moles of acid reacted</u>, using the <em>HBr solution's concentration and volume</em>:

  • Molarity = Moles / Volume
  • Molarity * Volume = Moles
  • 0.112 M * 12.4 mL = 1.389 mmol HBr

Now we <u>convert HBr moles to Ca(OH)₂ moles</u>, using the stoichiometric ratio:

  • 1.389 mmol HBr * \frac{1mmolCa(OH)_{2}}{2mmolHBr} = 0.6944 mmol Ca(OH)₂

Finally we <u>calculate the molarity of the Ca(OH)₂ solution</u>, using the <em>given volume and calculated moles</em>:

  • 0.6944 mmol Ca(OH)₂ / 15.2 mL = 0.0457 M
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I'll give 40 pts for this one but pls help me....
Ivenika [448]
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3 0
3 years ago
What gets reduced in an electrolytic cell made with nickel and copper electrodes?
jekas [21]

Answer:

D. Ni²⁺  

Explanation:

We know at once that the answer cannot be A or C, because Ni and Cu are already in their lowest oxidation states.

The correct answer must be either B or D.

An electrolytic cell is the opposite of a galvanic cell. In the former, the reaction proceeds spontaneously. In the latter, you must force the reaction to occur.  

One strategy to solve this problem is:

  1. Look up the standard reduction potentials for the half reaction·
  2. Figure out the spontaneous direction.
  3. Write the equation in the reverse direction.

1. Standard reduction potentials

                                E°/V

Cu²⁺ + 2e⁻ ⟶ Cu; 0.3419

Ni²⁺ + 2e⁻ ⟶ Ni;  -0.257

2. Galvanic Cell

We reverse the direction of the more negative half cell and add.

                                       <u>E°/V </u>

Ni ⟶ Ni²⁺ + 2e⁻;           0.257

<u>Cu²⁺ + 2e⁻ ⟶ Cu;      </u>   0.3419

Ni + Cu²⁺ ⟶ Cu + Ni²⁺; 0.599

This is the spontaneous direction.

Cu²⁺ is reduced to Cu.

3. Electrochemical cell

                                        <u>E°/V</u>

Ni²⁺ + 2e⁻ ⟶ Ni;           -0.257

<u>Cu ⟶ Cu²⁺ + 2e⁻;        </u> <u>-0.3419</u>

Cu + Ni²⁺ ⟶ Ni + Cu²⁺; -0.599

This is the non-spontaneous direction.

Ni²⁺ is reduced to Ni in the electrolytic cell.

8 0
3 years ago
How many electrons would be found in the Ion who’s symbol is I-
Vesnalui [34]

Answer:

54

Explanation:

Given symbol of the element:

                   I⁻

Number of electrons found in an ion with the symbol:

  This is a iodine ion:

         For an atom of iodine:

                   Electrons  = 53

                   Protons  = 53

                   Neutrons  = 74

An ion of iodine is one that has lost or gained electrons.

For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.

  So, number of electrons  = 53 + 1  = 54

The number of electrons in this ion is 54

6 0
3 years ago
What is the pH of a solution with a 1.50x10-9 M hydroxide ion concentration?
dimaraw [331]

Answer: 5.18

Explanation:

Mathematically, pOH is expressed as

pH = -log(OH-)

where OH-is the concentration of hydroxide ion

So, pOH calculations are as follows

pOH = -log(1.50x10-9 M)

pOH = -(-8.82)

pOH = 8.82 [the two minus signs cancelled out]

Since pOH = 8.82; apply the formula

pH + pOH = 14 to get pH of the solution

Hence, pH + pOH = 14

pH + 8.82 = 14

pH = 14 - 8.82

pH = 5.18

Thus, the pH of a solution with a 1.50x10-9 M hydroxide ion concentration is 5.18 (slightly acidic)

4 0
4 years ago
Help please please please please
Rom4ik [11]

Answer:

D. 18.7 grams

Explanation:

The coefficients are the key.

Create a proportion with them, and the molar mass, and then solve for x:

\frac{2}{3}  =  \frac{x}{28}  \\ 3x = 2(28) \\ 3x = 56 \\ x = 18.666... = 18.7

7 0
4 years ago
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