3 years ago

What is the oxidation state for the oxygen atom in na 2 o 2 ?

1 answer:

4 0

$Na_{2}O_{2}

Na in compounds has oxidation number +1 only.

So, Na_{2}^{+1}O_{2}^{x}

2*(+1)+2x=0, x=-1.

Oxidation number oxygen in Na_{2}O_{2} is - 1.$

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