We use the given masses of the reactants to calculate the moles of Mn and Cl. Empirical formula represents the simplest mole ratio of atoms present in a compound.
Moles of Mn = 
Moles of Cl = 
= 0.710 mol Cl
Simplest mole ratio: 
So the empirical formula is 
The class can break or if you put it in cold water it can cool down down fast.
Answer:
8.5 moles of Al₂O₃ will formed
Explanation:
Given data:
Number of moles of Al = 17 mol
Number of moles of Al₂O₃ formed = ?
Solution:
Chemical equation:
4Al + 3O₂ → 2Al₂O₃
Now we will compare the moles of Al₂O₃ with Al.
Al : Al₂O₃
4 : 2
17 : 2/4×17 = 8.5 mol
8.5 moles of Al₂O₃ will formed.
The lattice energy of the compounds is distributed in the following decreasing order of magnitude: MgO > CaO > NaF > KCl.
<h3>KCl or NaF, which has a higher lattice energy?</h3>
The lattice energy increases with increasing charge and decreasing ion size.(Refer to Coulomb's Law.)MgF2 > MgO.Following that, we can examine NaF and KCl (both of which have 1+ and 1-charges), as well as atomic radii.NaF will have a larger LE than KCl since Na is smaller then K and F was smaller than Cl.
<h3>MgO or CaO, which has a larger lattice energy?</h3>
MGO is more difficult than CaO, hence.This is because "Mg" (two-plus) ions are smaller than "Ca" (two-plus) ions in size.MgO has higher lattice energy as a result.
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Molality=mol/kg
342/171
=2m
Hope this helped :)
