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BaLLatris [955]
3 years ago
6

If the number of moles of gas is doubled at constant temperature and volume, the pressure of the gas:__________

Chemistry
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:

answer is b

use pv=nRT

p directly proportional to moles(n)

p1/p2=n1/n2

p/p2=n/2n

p2=2p

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Answer : The ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

Solution :  Given,

K_p=1.5\times 10^6

p_{O_2} = 0.21 atm

The given equilibrium reaction is,

NO(g)+\frac{1}{2}O_2\rightleftharpoons NO_2(g)

The expression of K_p will be,

K_p=\frac{(p_{NO_2})}{(p_{NO})\times (p_{O_2})^{\frac{1}{2}}}

Now put all the given values in this expression, we get:

1.5\times 10^6=\frac{(p_{NO_2})}{(p_{NO})\times (0.21)^{\frac{1}{2}}}

\frac{(p_{NO_2})}{(p_{NO})}=(1.5\times 10^6)\times (0.21)^{\frac{1}{2}}

\frac{(p_{NO_2})}{(p_{NO})}=6.87\times 10^5

Therefore, the ratio of p_{NO_2} to p_{NO} is, 6.87\times 10^5

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3 years ago
What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm
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Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

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Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

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Round to three significant figures, and you're done.

=1.78 % error



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