Your answer is correct, I do not understand why it would be wrong.
The electron accepting tendency of an atom is known as the tendency of an atom to accept an electron. This is ranked on a scale of 0.7 to 3.98 and these species have the following values:
F: 3.98
O: 3.44
C: 2.55
Be: 1.57
Li: 0.98
Answer:
Highest speed: He
Lowest speed: CO2
Explanation:
The rms speed (average speed) of the molecules/atoms in an ideal gas is given by:
where
R is the gas constant
T is the absolute temperature of the gas
M is the molar mass of the gas, which is the mass of the gas per unit mole
From the equation, we see that at equal temperatures, the speed of the molecules in the gas is inversely proportional to the molar mass: the higher the molar mass, the lower the speed, and vice-versa.
In this problem, we have 5 gases:
(CO2) (O2) (He) (N2) (CH4)
Their molar mass is:
CO2: 44 g/mol
O2: 16 g/mol
He: 4 g/mol
N2: 14 g/mol
CH4: 16 g/mol
The gas with lowest molar mass is Helium (He): therefore, this is the gas with greatest average speed.
The gas with highest molar mass is CO2: therefore, this is the gas with lowest average speed.
The intensity of a sound describes <em>its loudness at a particular distance</em><em />
Sound intensity is factored by the ear's sensitivity to the particular frequencies contained in a sound
Sound loudness describes the strength of the ear's perception of a sound.
These two points being said, if the ear is more sensitive to a frequency, that sound will be louder to us than sounds at different frequencies that might not be as sensitive to our ears. <em>So, the more intense the sound, the louder it is ;)</em>
Thank you for your question! I hope this helped! Have an amazing day! :D
In a voltaic cell there are two electrodes: anode and cathode.
On the cathode, the reaction that occurs is reduction, which means that the metal gains electrons.
On the anode the reaction is oxidation, which means that the metal loses electrons.
In this voltaic cell the reaction on the anode is:
Zn --> Zn 2+ + 2e-, i.e. option C.
Answer: option C.
