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3 years ago

Im not doing the math-

Chemistry

2 answers:

GREYUIT [131]3 years ago

7 0

The answer is 0.36 m/s credit to the guy above me (give him Brainlyist) but I also had to do this assessment.

BigorU [14]3 years ago

3 0

The average speed of the blocks are 0.36 m/s.
Explanation:
Average speed is defined as the ratio of distance covered per unit time. So if it is said that blocks are pulled to 0.9 m in the right side. This means the blocks cover a distance of 0.9 m from the origin and that distance is covered in 2.5 s. Thus, the average speed can be calculated from the change in speed with respect to time. As at time t = 0 , the speed is also zero, and at time t = 2.5 s , the speed will be
Since, in this case, the speed is equal to the average speed of blocks. So the average speed of the blocks will be 0.36 m/s.

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4 years ago

What is the molarity of a solution of 10% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass? The density of the

Gekata [30.6K]

Answer:

a. 0.528 M ..

Explanation:

Hello!

In this case, since the given by-mass percent can be written as:

$\frac{10gCdSO_4}{100g\ sol}$

By using the density and molar mass of the solute, cadmium sulfate, we can compute the molarity, by also making sure we convert from mL to L of solution:

$M=\frac{10gCdSO_4}{100g\ sol}*\frac{1molCdSO_4}{208.46gCdSO_4} *\frac{1.10g\ sol}{1mL\ sol} *\frac{1000mL\ sol}{1L\ sol} \\\\M=0.528M$

Thereby, the answer is a. 0.528 M .

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3 years ago

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kondor19780726 [428]

$\huge{\mathbb{\tt { QUESTION↓}}}$

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