I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx
The formula that we will going to use in this question is simply P1V1/T1 = P2V2/T2 where T is the constant.
P1V1 = P2V2
P2 = P1V1/V2 = (V1 / V2) x P2 = (13.0 L / 6.5 L) x 0.76 atm = 1.5 atm
The answer in this question is 1.5 atm
Answer:
54%
Explanation:
We are given that
S.D=4.2 lb
Mean=
We have to find the percentage of household throw out at least 9 lb of paper a week.
Normal distribution formula :

We have a=9


%
Hence, the percentage of household throw out at least of paper a week=54%
Answer:
<h2>
2.8×10^-3</h2>

<u>0.0028125N</u><u> </u>