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2 years ago

7

Select the correct answer.

2 answers:

Natali [406]2 years ago

8 0

its b hoped i helped

JulijaS [17]2 years ago

7 0

actually , potential energy should not be wrong. ive taken this quiz with the same question and D. was the answer .

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1123123213213242141241

schepotkina [342]

Answer:

thanks for the points

Explanation:

8 0

2 years ago

the velocity of a sound on a particular day outside is 331 meters/second. what is the frequency of a tone if it has a wavelength

hichkok12 [17]

Wavelength*frequency=velocity
(331m/s)/(.6m)
Frequency = 551.666 1/s

3 0

2 years ago

Object A of mass M is moving east at speed v. It collides with object B of mass 2M that was initially at rest. The motion of the

Firlakuza [10]

Answer:

$v_B=\frac{v}{3}$

Explanation:

Given that:

mass of object A, $m_A=M$

mass of object B, $m_B=2M$

speed of object A, $v_A=v$

So, according to the conservation of momentum, the momentum before collision is equal to the momentum after conservation.

$m_A.v+m_B\times 0=m_A\times v_A +m_B\times v_B$

$M\times v+0 = M\times \frac{v}{3}+2M\times v_B$

$2M\times v_B= \frac{2M\times v}{3}$

$v_B=\frac{v}{3}$

3 0

3 years ago

A common type of succession that occurs on a surface where an ecosystem has previously existed

MrRissso [65]

Secondary succession, the more common type of succession, occurs on a surface where an ecosystem has previously existed. It occurs in ecosystems that have been disturbed or disrupted by humans, animals, or by natural processes such as storms, floods, earthquakes, and volcanoes.

6 0

2 years ago

A hollow spherical shell with mass 1.95 kg rolls without slipping down a slope that makes an angle of 39.0 ∘ with the horizontal

irinina [24]

Answer:0.323

Explanation:

mass of spherical shell=1.95 kg

inclination $\theta =39^{\circ}$

Friction $(f_r)$ will oppose the motion of shell

$mgsin\theta -f_r=ma$

where a=acceleration

a is given by

$a=\frac{gsin\theta }{1+\frac{I}{mr^2}}$

I=moment of inertia $=\fac{2mr^2}{3}$

$a=\frac{3gsin\theta }{5}$

$f_r=mg\sin \theta -\frac{3mgsin\theta }{5}$

$f_r=\frac{2mgsin\theta }{5}$

and $f_r=\mu N$

$f_r=\mu mg\cos \theta$

$\mu mg\cos \theta =\frac{2mgsin\theta }{5}$

$\mu =\frac{2}{5}\times \tan \theta$

$\mu =0.323$

4 0

2 years ago