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AlexFokin [52]
3 years ago
7

Select the correct answer.

Physics
2 answers:
Natali [406]3 years ago
8 0

its b hoped i helped

JulijaS [17]3 years ago
7 0

actually , potential energy should not be wrong. ive taken this quiz with the same question and D. was the answer .

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If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
Gala2k [10]

Answer:

If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

7 0
3 years ago
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What does infrastructure refer to? process by which a nation improves the economic, political, and social well-being of its peop
Travka [436]

Answer:

Infrastructure is the term for the basic physical systems of a business or nation—transportation, communication, sewage, water, and electric systems are all examples of infrastructure

Explanation:

These systems tend to be high-cost investments and are vital to a country's economic development and prosperity.

7 0
3 years ago
An object traveling at 1.5 rad
Veronika [31]

The object's final velocity, given the data is 10.5 rad/s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

<h3>How to determine the final velocity</h3>

The following data were obtained from the question

  • Initial velocity (u) = 1.5 rad/s
  • Acceleration (a) = 0.75 rad/s²
  • Time (t) = 12 s
  • Final velocity (v) = ?

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

6 0
2 years ago
Red light from three separate sources passes through a diffraction grating with 5.60×105 slits/m. The wavelengths of the three l
shtirl [24]

Answer:

I can help

Explanation:

6 0
3 years ago
A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0
3 years ago
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