When the diver reaches maximum height, the upward velocity will be zero.
We shall use the formula
v^2 = u^2 - 2gh
where
v = 0 (velocity at maximum height)
u = 1.2 m/s, intial upward velocity
g = -9.8 m/s^2, gravitational acceleration (downward)
h = maximum height attained above the diving board.
Therefore
0 = 1.2^2 - 2*9.8*h
h = 1.2^2/(2*9.8) = 0.0735 m
Answer: 0.074 m (nearest thousandth)
Answer:
Explanation:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m/150s=2ms^−1. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m. Since it is a straight road and he jogs in a single direction in this case, his displacement is equal to 300m.
Hence, his average velocity is 300m/150s=2ms^−1
(b) Then it is given that he turns back and points B and jogs on the same road but in the opposite direction for a time interval for 1 minute and covers a distance of 100m.If we consider the whole motion of Joseph, i.e. from point A to point C, then he covers a total distance of 300m+100m=400m. And he covers this total distance in a time interval of 2.5min+1min=3.5min=210s.
Therefore, his average speed for this journey is 400m210s=1.9ms−1.
For the same journey is displacement is equal to the distance between the points A and C,i.e. 300m−100m=200m.
Hence, his average velocity for this case is 200m/210s=0.95ms^−1
Answer:
I think it is acute angle.
Explanation:
Because it is an angle between 0° and 90°. Hope this answer wil help you.
Answer:
19,551 J!
Explanation:
The formula is PE = ham (h=height, a= acceleration or 9.8, m= mass)
PE = (95)(9.8)(21)
PE = 19,551 Joules
Answer:
The value of θ can be determined by slope of graph as function of square of time.
Explanation:
Lets take
Mass = m
Angle of inclination =θ
From diagram
mg sinθ = m a
So
a=g sinθ
We know that
Given that block is in rest position initially.
u= 0
We can say that
S∝ t² If we assume that t and x and S as y y= m x
Here slope ,m
So the value of θ can be determined by slope of graph as function of square of time.
