Answer:
Final temperature is 34.2 °C
Explanation:
Given data:
mass of metal = 125 g
temperature of metal = 93.2 °C
mass of water v= 100 g
temperature of water = 18.3 °C
specific heat of meta is = 0.900 j/g. °C
specific heat of water is = 4.186 j/g. °C
final temperature of water and metal = ?
Solution:
Q = m . c . ΔT
ΔT = T2-T1
now we will put the values in equation
Q1 = m . c . ΔT
Q1 = 125 g. 0.900 j/g. °C .93.2°C - T2
Q1 = 112.5 (93.2°C - T2)
Q1 =10,485 - 112.5T2
Q2 = m . c . ΔT
Q2 = 100 . 4.186. (T2- 18.3)
Q2 = 418.6 . (T2- 18.3)
Q2 = 418.6T2 - 7660.38
10,485 - 112.5T2 = 418.6T2 - 7660.38
10,485 + 7660.38 = 418.6T2+ 112.5T2
18145.38 = 531.1 T2
T2 = 18145.38/531.1
T2 = 34.2 °C
The correct answer is realistic and reliable
The chart is attached below and the options are as follow,
A Benzene
B Methanol
C Hexane
D Octane
Answer: Option-B (Methanol) is the correct answer.
Explanation: As we know that the substance given to student is soluble in water. Therefore, those substances which are soluble in water are
polar in nature because water is
polar in nature and
Like Dissolves Like.
Hence, in chart it can easily be seen that
Methanol is also polar in nature due to presence of -O-H (polar) bond. So, the substance will dissolve in it.
Answer:
Independent variables are ones that can be controlled and dependent variables are results of these changes. So, in question a, an independent variable is amount of a released energy, in these case in form of heat. We reduced that amount and as a result we get a dependent variable as high temperature of chocolate for longer time, so we changed time of a heat releasing from chocolate. In question b, an independent variable is temperature of water, and a dependent variable is amount of produced oxygen. In question c, an independent variable is an intensity of exercise. When we change the intensity of exercise, as a results, breathing rate is changed, which is dependent variable.
Explanation:
Answer:
C
Explanation:
Temperature is directly related to kinetic energy (KE). As we raise temperature, we are raising KE, as well. Particles with more KE move more quickly and with more force.
This means that these particles are more likely to collide with each other and react to allow the chemical reaction to follow through. In turn, if the chemical reaction is more likely to go to completion, the reaction rate increases, eliminating A and B.
The concentration of the solute is not affected by the temperature; in other words, temperature will not increase or decrease the amount of solute in the solution, so eliminate D.
Thus the answer is C.
Hope this helps!
