A is a model of a decomposition reaction
The balanced chemical equation in a basic solution will be,
→ ![BrO_{3} ^{-} + 4H_{2} O+4Fe^{+2}](https://tex.z-dn.net/?f=BrO_%7B3%7D%20%5E%7B-%7D%20%20%2B%204H_%7B2%7D%20O%2B4Fe%5E%7B%2B2%7D)
The reaction in which oxidation and reduction reaction takes place simultaneously is called redox reaction or oxidation - reduction reaction .
Rules for the balanced chemical equation in a basic solution are :
- First write half - reaction.
- Now balancing the main atoms in the reaction
- Now balancing the hydrogen and oxygen atoms on both sides of the reaction .
- If the oxygen atoms is not balance on both side then add water molecule at that side at that side where more number of oxygen atom is present.
- If the hydrogen atom are not balanced on both side then add hydroxide ion at that side of where less number of hydrogen are present.
- Now at last balance the charge.
Therefore, the balanced chemical equation in a basic solution will be,
→ ![BrO_{3} ^{-} + 4H_{2} O+4Fe^{+2}](https://tex.z-dn.net/?f=BrO_%7B3%7D%20%5E%7B-%7D%20%20%2B%204H_%7B2%7D%20O%2B4Fe%5E%7B%2B2%7D)
To learn more about redox reaction
brainly.com/question/13293425
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A dependent variable (y) is a variable that relies on the x value. i hope this helps!!!
Answer:
The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Explanation:
We are given that
Aqueous solution that contains 22.9% NaOH by mass means
22.9 g NaOH in 100 g solution.
Mass of NaOH(WB)=22.9 g
Mass of water =100-22.9=77.1
Na=23
O=16
H=1.01
Molar mass of NaOH(MB)=23+16+1.01=40.01
Number of moles =![\frac{Given\;mass}{Molar\;mass}](https://tex.z-dn.net/?f=%5Cfrac%7BGiven%5C%3Bmass%7D%7BMolar%5C%3Bmass%7D)
Using the formula
Number of moles of NaOH![(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}](https://tex.z-dn.net/?f=%28n_B%29%3D%5Cfrac%7BW_B%7D%7BM_B%7D%3D%5Cfrac%7B22.9%7D%7B40.01%7D)
![n_B=0.572moles](https://tex.z-dn.net/?f=n_B%3D0.572moles)
Molar mass of water=16+2(1.01)=18.02g
Number of moles of water![(n_A)=\frac{77.1}{18.02}](https://tex.z-dn.net/?f=%28n_A%29%3D%5Cfrac%7B77.1%7D%7B18.02%7D)
![n_A=4.279 moles](https://tex.z-dn.net/?f=n_A%3D4.279%20moles)
Now, mole fraction of NaOH
=![\frac{n_B}{n_B+n_A}](https://tex.z-dn.net/?f=%5Cfrac%7Bn_B%7D%7Bn_B%2Bn_A%7D)
![=\frac{4.279}{0.572+4.279}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4.279%7D%7B0.572%2B4.279%7D)
=0.882
Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882
Answer:
because that is the last group the ones before it are more reactive im sorry if this not what you were looking for.