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weeeeeb [17]
3 years ago
9

The voltage between two points in a circuit is 5 V. If the resistance between

Physics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

B. 0.063 A

Explanation:

I just took the quiz.

lisabon 2012 [21]3 years ago
3 0

Answer:

B

Explanation:

i worked it out on a diffrent sheet so its hard to explain

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If a car is travelling 120 miles southbound for 3 hours, what is the velocity?
Zinaida [17]

Answer:

40 miles / hour south

Explanation:

120 miles/3 hours = 40 miles / hour

4 0
3 years ago
Read 2 more answers
a block is pushed up a frictionless 40 incline. if the initial velocity after the push is 5.00 m/s. how far along the incline do
Lana71 [14]

Answer:

d=1.982m, t=1.019s

Explanation:

There are different approaches we can take to solve this problem. You could either solve this by using conservation of energy or by taking a kinematic approach. I'll solve this by using kinematics. So, the very first thing we need to do in order to solve this is do a drawing of the situation so we can analyze it better. (See attached picture).

So, since we are talking about an inclined plane, we can see that the force of gravity is being split into an x and y components if we incline the axis of coordinates. Taking this into account we can see that:

\sum F_{x}=ma_{x}

Since there is no friction in our system, then the only force acting upon the box is the force of gravity, or weight. Since we are taking the upwards direction as the positive direction of movement, we can say that the force of gravity is excerting a negative influence on our box, so this acceleration will be negative, so our sum of forces will now look like this:

-mg sin(40^{o})=ma

we can cancel the masses out so we can see that:

a=-g sin(40°)

a=-9.81m/s^{2} sin(40^{o})

We have now enough information to solve our problem.

we can take the following equation to find the distance the block travels up the incline:

x=\frac{V_{f}^{2}-V_{0}^{2}}{2a}

we know the final velocity must be zero, so we can use the provided data to solve our formula:

x=\frac{(0)^{2}-(5m/s)^{2}}{2(-9.81m/s^{2})sin 40^{o}}

which yields:

x=1.982m

In order to find the time it takes for the block to return to its original position we can use the following formula:

x=V_{0}t+\frac{1}{2}at^{2}

since x=0 is the starting point we can use that to solve our equation:

0=5t+\frac{1}{2}(-9.81sin 40^{o})t^{2}

which simplifies to:

0=5t-4.905t^{2}

which can now be solved for t

t(5-4.905t)=0

t=0                and          5-4.905t=0

t=0                 and         t=\frac{5}{4.905}=1.019

so the time it takes the block to return to its original position is

t= 1.019s

6 0
3 years ago
What do the arrows at point three indicate
Maru [420]
Maybe show a picture ? I don’t get the question .
5 0
3 years ago
Which of the following is not one of the four muscle shapes?
zhenek [66]

Answer:

When elements bond together or when bonds of compounds are broken and form a new substance

Explanation:

3 0
3 years ago
(I) A 0.145-kg baseball pitched at 31.0 m/s is hit on a horizontal line drive straight back at the pitcher at 46.0 m/s. If the c
tangare [24]

Answer:

<em>The force between the ball and the bat = 2233 N</em>

Explanation:

Force: This can be defined as the product of force and its acceleration.

The S.I unit of Force is Newton (N)

F = ma .............................. Equation 1

Where F = Force , m = mass of the ball, a = acceleration of the ball.

where

a = (v-u)/t..................... Equation 2

Where v = final velocity of the ball, u = initial velocity of the ball, t = time of contact between the ball an the bat.

<em>Given: v = 46 m/s u = - 31 m/s (it hit an horizontal line drive back at the pitcher), t = 5×10⁻³ s</em>

<em>Substituting these values into equation 2,</em>

<em>a = [46-(31)]/(5×10⁻³ )</em>

a = 77<em>×10³/5</em>

<em>a = 15.4×10³ m/s².</em>

<em>Also given m = 0.145 kg</em>

<em>Substituting into equation 1,</em>

F = 0.145(15.4<em>×10³ )</em>

F = 2233 N

<em>Thus the force between the ball and the bat = 2233 N</em>

<em></em>

8 0
3 years ago
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