Answer:
1/4 times your earth's weight
Explanation:
assuming the Mass of earth = M
Radius of earth = R
∴ the mass of the planet= 4M
the radius of the planet = 4R
gravitational force of earth is given as = ![\frac{GM}{R^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BGM%7D%7BR%5E%7B2%7D%20%7D)
where G is the gravitational constant
Gravitational force of the planet = ![\frac{G4M}{(4R)^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BG4M%7D%7B%284R%29%5E%7B2%7D%20%7D)
=![\frac{G4M}{16R^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BG4M%7D%7B16R%5E%7B2%7D%20%7D)
=![\frac{GM}{4R^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BGM%7D%7B4R%5E%7B2%7D%20%7D)
recall, gravitational force of earth is given as = ![\frac{GM}{R^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BGM%7D%7BR%5E%7B2%7D%20%7D)
∴Gravitational force of planet = 1/4 times the gravitational force of the earth
you would weigh 1/4 times your earth's weight
I think it should be D as momentum is the product of mass and velocity...
B
because it will pick it up while coming down not just flowing on low land<span />
Answer:
v = 2591.83 m/s
Explanation:
Given that,
The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,
![qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s](https://tex.z-dn.net/?f=qE%3DqvB%5C%5C%5C%5Cv%3D%5Cdfrac%7BE%7D%7BB%7D%5C%5C%5C%5Cv%3D%5Cdfrac%7B1.27%5Ctimes%2010%5E3%7D%7B0.49%7D%5C%5C%5C%5Cv%3D2591.83%5C%20m%2Fs)
So, the speed of the electron is 2591.83 m/s.
Answer:
If child weight is equal to rope force then child will move with uniform speed
or we can say that the child will remain at rest in his position
Explanation:
As we know that child is hanging by rope
so here there will be two forces on the child
1) Weight or gravitational force which act vertically downwards
2) Tension in the rope which act vertically upwards
Now if child will accelerate upwards then tension force must be more than the weight of the child
If tension force is less than the weight then child will decelerate and his speed will decrease
if tension force is equal to child weight then in that case the child will remain at rest or it will move with same speed