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2 years ago

What is the difference between heat capacity and specific heat?.

Physics

1 answer:

Mazyrski [523]2 years ago

6 0

Answer:

Heat capacity is the amount of heat required to raise the temperature of an object by 1oC. The specific heat of a substance is the amount of energy required to raise the temperature of 1 gram of the substance by 1oC.

Explanation:

The answer is above.

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Hydrogen fluoride gas (HF) and sodium hydroxide (NaOH) react in a test tube. They form water and sodium fluoride (NaF). Which ty

AfilCa [17]

This reaction is a double replacement reaction. Hydrogen in the hydrogen fluoride gets replaced by sodium of the sodium hydroxide. HF is a weak acid and NaOH is a strong base. So, double replacement produces sodium fluoride and water molecules.

6 0

3 years ago

1 point

Sonja [21]

The answer would be 0.21 i believe if you use something we called F/Ma in grade school

6 0

3 years ago

The tread on a tire helps the car hold the road due to A) friction. B) gravity. C) inertia. D) momentum.

NemiM [27]

The answer would be friction

8 0

3 years ago

He drives 150 meters in 18 seconds. Assuming constant speed, what is his speed in meters per second?

ira [324]

Answer:

Explanation:

Givens

d = 150 meters

t = 18 seconds

r (rate) = ?

Formula

r = d/t

Solution

r = 150/18

r = 8.33 m/s

4 0

3 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$