Answer:
1.791 MN
Explanation:
Thrust of the rocket can be found using the relation
T = v.dm/dt, where
T = thrust off the rocket
v = speed of the rocket, 9 km/s = 9000 m/s
dm/dt = rate at which fuel burns, 199 kg/s
Substituting the values into the formula, we have
T = 9000 * 199
T = 1791000 N
T = 1.791*10^6 N
Since 1 MN = 10^6, thus
T = 1.791 MN
exit temperature of air is 776.128k
the mass flow rate of exhaust gases is 14.89kg/s
Explanation: plz brainly me
The answer is C.
The magnitude is greater and the motion is going in the direction of the arrow meaning it’s a straight line in the direction will not change
Answer:
a
Explanation:
it increases with increasing height