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ira [324]
3 years ago
7

WILL GIVE BRAINLIEST.

Physics
1 answer:
Tanzania [10]3 years ago
3 0

The product of (mass) x (acceleration) is equal to (force).

So if (force) doesn't change and (mass) changes, then
(acceleration) has to change in the other direction from (mass)
in order to keep their product constant.

If the (forces) on both wagons are equal but one wagon has
double the (mass) of the other, then the more massive wagon
has  (1/double)  =  1/2  the acceleration of the less massive one.
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What is the sidereal period used in Kepler’s third law?
klasskru [66]
His law exaplins/shows that the average distance of a planet from the Sun cubed is directly proportional to the orbital period squared.
3 0
3 years ago
Assume that a satellite orbits mars 150km above its surface. Given that the mass of mars is 6.485 X 10^23kg, and the radius of m
Kisachek [45]
<span>3598 seconds The orbital period of a satellite is u=GM p = sqrt((4*pi/u)*a^3) Where p = period u = standard gravitational parameter which is GM (gravitational constant multiplied by planet mass). This is a much better figure to use than GM because we know u to a higher level of precision than we know either G or M. After all, we can calculate it from observations of satellites. To illustrate the difference, we know GM for Mars to within 7 significant figures. However, we only know G to within 4 digits. a = semi-major axis of orbit. Since we haven't been given u, but instead have been given the much more inferior value of M, let's calculate u from the gravitational constant and M. So u = 6.674x10^-11 m^3/(kg s^2) * 6.485x10^23 kg = 4.3281x10^13 m^3/s^2 The semi-major axis of the orbit is the altitude of the satellite plus the radius of the planet. So 150000 m + 3.396x10^6 m = 3.546x10^6 m Substitute the known values into the equation for the period. So p = sqrt((4 * pi / u) * a^3) p = sqrt((4 * 3.14159 / 4.3281x10^13 m^3/s^2) * (3.546x10^6 m)^3) p = sqrt((12.56636 / 4.3281x10^13 m^3/s^2) * 4.458782x10^19 m^3) p = sqrt(2.9034357x10^-13 s^2/m^3 * 4.458782x10^19 m^3) p = sqrt(1.2945785x10^7 s^2) p = 3598.025212 s Rounding to 4 significant figures, gives us 3598 seconds.</span>
8 0
3 years ago
PV = nRT, is the a. equation of state of an ideal gas
romanna [79]

Ideal gas law:

PV = nRT

P = pressure, V = volume, n = # of moles, R = gas constant, T = temperature

Equipartition theorem:

Each degree of freedom that a molecule has adds 0.5kT to its total internal energy where k = Boltzmann's constant and T = temperature

2nd law of thermodynamics:

A set of governing principles that restrict the direction of net heat flow (always hot to cold, heat engines are never 100% efficient, entropy always tends to increase, etc)

Clearly the answer is Choice A

3 0
3 years ago
Describe the sun. Include its structure (layers), relative size, location, and effects of its magnetic field. Where does the sun
Salsk061 [2.6K]

Answer: Nuclear fusion.

Explanation: The sun is a medium-sized star, its radius is  695.510 km and its mass is equivalent to that obtained by bringing together about 110 planets equal to Earth (6371 km is its radius).

It has six layers: The core, the radioactive zone, the convective zone, the photosphere, the chromosphere and the corona.

Magnetic field disruptions near active regions can generate strong explosions in the sun such as sun flashes and coronal mass ejections. The degree of complexity of the sun´s magnetic field increases and decreases with the course of each sunspot cycle.  

Sir Arthur Eddington was the first to evaluate all the data and dared to conjecture that nuclear fusion, the process that creates heavy elements from the fusion of lighter ones, could be responsible for the great production of the sun´s energy; this process make the sun´s energy was taken for the earth and the planet get back to the sun recycled energy. The sun has a very large and complex magnetic field; the average magnetic field of the sun is approximately 1 Gauss, almost twice as strong as the average magnetic field of the Earth´s surface (approximately 0.5 Gauss). Because the surface of the sun is more than 12.000 times larger than the Earth, the overall influence of the sun´s magnetic field is immensely large.

6 0
3 years ago
the gasoline in a car does 40000 j of work on a car and generates a constant force of 20 n. how far did the car go?
NikAS [45]

     Work  =  (force) x (distance)

     40,000 J  =  (20 N) x (distance)

     Distance  =  (40,000 J) / (20 N)

                    =    2,000 meters

                    =     2 kilometers.

(20 N is not a huge force when it's being used to move a car.
It's only about  4.5 pounds.) 
8 0
3 years ago
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