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3 years ago

WILL GIVE BRAINLIEST.

1 answer:

3 0

The product of (mass) x (acceleration) is equal to (force).

So if (force) doesn't change and (mass) changes, then
(acceleration) has to change in the other direction from (mass)
in order to keep their product constant.

If the (forces) on both wagons are equal but one wagon has
double the (mass) of the other, then the more massive wagon
has (1/double) = 1/2 the acceleration of the less massive one.

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List 5 possible effects of not adhering to standards of measurement

Bond [772]

Explanation:

Without the metric system, we'd have a different International System of Units, the metric system is important because 1mm is 0.1cm, 1 cm is 0.01m, with the imperial system the conversion is tedious. The most important feature of the metric system is its base in scientific fact and repeatable standards of measurement

3 0

2 years ago

"the student drops one cannonball, and exactly 1.0 s later drops the other cannonball from the same height. what is the time int

Elden [556K]

Answer;

1 second

Explanation;

Two objects moving at the same speed will always stay the same distance apart. If two objects are moving at different speeds, the distance between them must change.

Therefore; if the distance will be the same and the speed is also the same then the time taken will be the same.

6 0

3 years ago

You want to manufacture a guitar such that the instrument will be in tune when each of the strings are tightened to the same ten

charle [14.2K]

Answer:

0.000507 kg/m

Explanation:

L = Length of string

T = Tension

$\mu$ = Mass density of string

E denotes the E string

D denotes the D String

Frequency is given by

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}$

$f\propto \sqrt{\dfrac{1}{\mu}}$

$\dfrac{f_D}{f_E}=\sqrt{\dfrac{\mu_E}{\mu_D}}\\\Rightarrow \mu_E=\dfrac{f_D^2}{f_E^2}\mu_D\\\Rightarrow \mu_E=\dfrac{146.83^2}{329.63^2}\times 0.00256\\\Rightarrow \mu_E=0.000507\ kg/m$

The mass density of the E string is 0.000507 kg/m

8 0

3 years ago

The number of bacteria in a certain population increases according to a continuous exponential growth model, with a growth rate

sveta [45]

Answer:

It would take approximately 289 hours for the population to double

Explanation:

Recall the expression for the continuous exponential growth of a population:

$N(t)=N_0\,e^{kt}$

where N(t) measures the number of individuals, No is the original population, "k" is the percent rate of growth, and "t" is the time elapsed.

In our case, we don't know No (original population, but know that we want it to double in a certain elapsed "t". We also have in mind that the percent rate "k" would be expressed in mathematical form as: 0.0024 (mathematical form of the given percent growth rate).

So we need to solve for "t" in the following equation:

$2\,N_0=N_0\,e^{0.0024\,t}\\\frac{2\,N_0}{N_0} =e^{0.0024\,t}\\2=e^{0.0024\,t}\\ln(2)=0.0024\,t\\t=\frac{ln(2)}{0.0024} \\t=288.811\,\, hours$

Which can be rounded to about 289 hours

6 0

3 years ago

Help please what law is happening in these pictures

Karolina [17]

Answer: boyles law I’m pretty sure

7 0

2 years ago