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tester [92]
3 years ago
13

A 76g ball is attached to a string that is 1.5m long. It is spun so that it completes two full rotations every second. What is t

he centripetal acceleration felt by the ball? m/s2
What is the Force tension on the string? N
Physics
1 answer:
Marat540 [252]3 years ago
4 0

The centripetal acceleration = 236.63 m/s²

The force = 17.98 N

<h3>Further explanation</h3>

Given

mass = 76 g = 0.076 kg

r = 1.5 m

f = 2 rps = 2 rotation per second

Required

The centripetal acceleration

The Force tension

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

r = radius, m  

The speed that is in the direction of the circle is called linear velocity  

Can be formulated:  

\tt \displaysyle v = 2 \pi.r.f

r = circle radius  

f = rotation per second (RPS)  

The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s

The centripetal acceleration : ac = v²/R = 236.63 m/s²

The force : F = m x ac = 0.076 x 236.63 = 17.98 N

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Answer:

The first force that the bungee jumper experiences is gravity, which pulls down on everything and makes the jumper fall. The gravitational force is almost exactly constant throughout the jump. During the bungee jumper's fall, he or she also experiences a force due to air resistance.

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3 years ago
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Goryan [66]

Answer:

The braking distance would be about nine times as long (assuming that acceleration during braking stays the same.)

Explanation:

Let u denote the initial velocity of the vehicle (20\; \text{mph} or 60\; \text{mph}) and let v denote the velocity of the vehicle after braking (0\; \text{mph}). Let x denote the braking distance.

Assume that the acceleration during braking are both constantly a in both scenarios. The SUVAT equations would apply. In particular:

\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a}\end{aligned}.

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Assuming that a (braking acceleration) stays the same, the braking distance x would be proportional to u^{2}, the square of the initial velocity.

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1 year ago
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The micrometer (1 μm) is often called the micron. (a) How many microns make up 3.0 km? (b) How many centimeters equal 3.0 μm? (c
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Answer:

3 x 10⁻⁹km

3 x 10⁻⁴cm

2.73 x 10⁶μm

Explanation:

 A micron is a subunit of measurement usually for length dimensions.

                     1μm   = 1 x 10⁻⁶m

a. How many microns make up 3km;

         Now convert to meter first;

                 1000m  = 1km

           So, 3km will be made up of 3000m

So;

          1 x 10⁻⁶m    =     1μm  

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b.  How many centimeters equal 3.0 μm?

            Since;

                        1μm   = 1 x 10⁻⁶m

                         3μm  = 3 x 1 x 10⁻⁶  = 3 x 10⁻⁶m

So;

            100cm  = 1m;

                  1m  = 100cm

             3 x 10⁻⁶m  = 3 x 10⁻⁶  x 10²   = 3 x 10⁻⁴cm

c. How many microns are in 3.0 yd?  

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              3yd  = 3 x 0.91  = 2.73m

So;

            1 x 10⁻⁶m    =     1μm  

              2.73m will give \frac{2.73}{1 x 10^{-6} }   = 2.73 x 10⁶μm

           

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Answer:

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assuming the constant k is the same

the relationship between the two forces is

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Explanation:

[ Refer to the attached file ]

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