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tester [92]
3 years ago
13

A 76g ball is attached to a string that is 1.5m long. It is spun so that it completes two full rotations every second. What is t

he centripetal acceleration felt by the ball? m/s2
What is the Force tension on the string? N
Physics
1 answer:
Marat540 [252]3 years ago
4 0

The centripetal acceleration = 236.63 m/s²

The force = 17.98 N

<h3>Further explanation</h3>

Given

mass = 76 g = 0.076 kg

r = 1.5 m

f = 2 rps = 2 rotation per second

Required

The centripetal acceleration

The Force tension

Solution

Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle  

\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}

F = centripetal force, N  

m = mass, Kg  

v = linear velocity, m / s  

r = radius, m  

The speed that is in the direction of the circle is called linear velocity  

Can be formulated:  

\tt \displaysyle v = 2 \pi.r.f

r = circle radius  

f = rotation per second (RPS)  

The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s

The centripetal acceleration : ac = v²/R = 236.63 m/s²

The force : F = m x ac = 0.076 x 236.63 = 17.98 N

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forsale [732]

Answer:

The extension of the wire is 0.362 mm.

Explanation:

Given;

mass of the object, m = 4.0 kg

length of the aluminum wire, L = 2.0 m

diameter of the wire, d = 2.0 mm

radius of the wire, r = d/2 = 1.0 mm = 0.001 m

The area of the wire is given by;

A = πr²

A = π(0.001)² = 3.142 x 10⁻⁶ m²

The downward force of the object on the wire is given by;

F = mg

F = 4 x 9.8 = 39.2 N

The Young's modulus of aluminum is given by;

Y = \frac{stress}{strain}\\\\Y = \frac{F/A}{e/L}\\\\Y = \frac{FL}{Ae} \\\\e = \frac{FL}{AY}

Where;

Young's modulus of elasticity of aluminum = 69 x 10⁹ N/m²

e = \frac{FL}{AY} \\\\e = \frac{(39.2)(2)}{(3.142*10^{-6})(69*10^9)} \\\\e = 0.000362 \ m\\\\e = 0.362 \ mm

Therefore, the extension of the wire is 0.362 mm.

8 0
3 years ago
Plzz answer this question ​
Vera_Pavlovna [14]
Mass does not change anywhere in the space .
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After finding the mass of the body multiply it by the given acceleration due to gravity.
Mg is the approximate force due to gravity between the mass and the planet.

I hope this may help you.
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What do geographers explore
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Answer:

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I  = pressure amplitude given = 0.2 W/m²

dB = decibel reading

decibel reading from the pressure amplitude is given as

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inserting the values in the above equation

dB = 10 log₁₀ (0.2/10⁻¹²)

dB = 10 log₁₀ (2 x 10⁻¹/10⁻¹²)

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