The temperature for the reaction is calculated as follows
delta H/ delta S
delta H=-70 Kj
delta S =-0.300 kj/k
temperature is therefore = -70kj/-0.300kj/k =233.33 K
Answer:
sulfur, selenium, and oxygen.
Explanation:
I got it right on my test
Answer:
The the empirical formula for magnesium chloride based on this experiment will be
Explanation:
Given that,
Mass of Mg = 0.50 g
Mass of magnesium chloride found = 1.99 g
Let the formula of magnesium chloride be
We know that,
Molar mass of Mg= 24 g/mol
Molar mass of magnesium chloride = (24x+35.5y) g/mol
We need to calculate the moles of Mg
Using formula of moles
Put the value into the formula
We need to calculate the mole of magnesium chloride
Using formula of moles
Put the value into the formula
The reaction will be,
We need to calculate the value of x and y
Using number of moles of Mg in reactant and product
Moles of Mg atom in reactant=Moles of Mg atom in product
Hence, The the empirical formula for magnesium chloride based on this experiment will be
Answer:
3rd law
Explanation:
when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
The reaction formula of this is N2 + 3H2 = 2NH3. So the ratio of mol number of N2 and NH3 is 1:2. The mol number of NH3 is 2.27*2=4.54 mol. So the mass is 4.54*17=77.18 g.